A. y= -4/5x+ 5/4 <br> B. y= -4/5x+ 3/2<br> C. y= -5/4x+ 3/2<br> D. y= -5/4x+ 5/4

28.6% of city employees ride the bus to work. Last year, 29.7% of city employees rode the bus to work. What is the relative chan

yaroslaw [1]

A percentage is a way to describe a part of a whole. The relative change from last year to this year is 3.7%.

<h3>What are Percentages?</h3>

A percentage is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25 which is equal to 25%.

To convert a fraction to a percentage, convert the fraction to decimal form and then multiply by 100 with the '%' symbol.

28.6% of city employees ride the bus to work, therefore, the final value is 28.6. While Last year, 29.7% of city employees rode the bus to work, therefore, the initial value is 29.7.

Since relative change means change with respect to some value. Thus, the relative value with respect to last year is,

Relative value = (29.7-28.6)/29.7 = 0.037 = 3.7%

Hence, the relative change from last year to this year is 3.7%.

Learn more about Percentages:

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8 0

1 year ago

A streetlamp has a 20 ft shadow that makes a 40° angle with the ground. which expression represents the height of the street lam

Oduvanchick [21]

Answer:

20 sin 40° ≈ 12.86 ft

Step-by-step explanation:

Let the height of the street lamp be x

Opposite angle is 40° and the shadow, the hypotenuse of the formed triangle is 20 ft.

sin 40° = x/20
x = 20sin 40°
x ≈ 12.86 ft

6 0

3 years ago

I need help on a mathematics question. I need an explanation.

romanna [79]

Start by dividing both sides by 2 to get $log(x)= \frac{1}{2}log(64)$ . Doing the math on the right, keeping in mind that logs have an unwritten base of 10, gives us $log_{10} (x)=.903089987$ . Rewriting this in exponential form is $10^{.903089987}=x$ . That means that x = 8. Not negative, only positive.

4 0

3 years ago

Solve the following equation for h.<br> r+3Q/h=t

Arada [10]

Answer:

$\bold{h=\dfrac{3Q}{t-r}}$

Step-by-step explanation:

$\bold{r+\frac{3Q}h=t}\\-r\qquad\ -r\\\bold{\frac{3Q}h=t-r}\\\cdot h\qquad \cdot h\\ \bold{3Q=(t-r)h}\\^{\div(t-r)\quad\div(t-r)}\\\bold{\dfrac{3Q}{t-r}=h}$

Or, if you mean (r+3Q)/h=t:

$\bold{\frac{r+3Q}h=t}\\{}\ \ \cdot h\quad\ \cdot h\\\bold{r+3Q=ht}\\{}\ \ \div t\qquad \div t\\\bold{\dfrac{r+3Q}{t}=h}\\\\\bold{h=\dfrac{r+3Q}{t}}$

4 0

3 years ago

Question and answer in picture

Andrews [41]

Answer:

i think the answer is B but don't take my word for it

5 0

3 years ago

Read 2 more answers

A. y= -4/5x+ 5/4 B. y= -4/5x+ 3/2 C. y= -5/4x+ 3/2 D. y= -5/4x+ 5/4