Answer:
100 m
Explanation:
44 km/h = 12.2 m/s
110 km/h = 30.6 m/s
Given:
Δx = 16 m
v₀ = 12.2 m/s
v = 0 m/s
Find: a
v² = v₀² + 2aΔx
(0 m/s)² = (12.2 m/s)² + 2a (16 m)
a = -4.67 m/s²
Given:
v₀ = 30.6 m/s
v = 0 m/s
a = -4.67 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (30.6 m/s)² + 2 (-4.67 m/s²) Δx
Δx = 100 m
Answer:
3.2m
Explanation:
Given parameters:
Frequency of the FM radio = 9.23 x 10⁷Hz
Velocity of the waves = 3 x 10⁸m/s
Unknown:
Wavelength of the wave = ?
Solution:
To solve for the wavelength of the wave, we need the velocity equation;
Velocity = frequency x wavelength.
Radio waves are all electromagnetic radiations produced by both electrical and magnetic fields perpendicularly oriented to one another.
Since the unknown is wavelength, we solve for it:
3 x 10⁸ = 9.23 x 10⁷ x wavelength
wavelength = 
wavelength = 3.2m
Answer:
Maximum torque on the wire is 
Explanation:
It is given that,
Diameter of the wire, d = 11.1 cm = 0.111 m
Radius of wire, r = 0.0555 m
Magnetic field, 
Current, I = 5 A
We need to find the maximum torque on the wire. Torque is given by :

Torque is maximum when, 



or

So, the maximum toque on the wire is
. Hence, this is the required solution.