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Alexandra [31]
3 years ago
9

As microwave light travels through a liquid, it moves at a speed of 2.2 x 108 m/s. If the frequency of this light wave is 1.1 x

108 Hz, what is the wavelength of this microwave?
Physics
1 answer:
Alexandra [31]3 years ago
7 0

λ = 2 m.

The easiest way to solve this problem is using the equation of frecuency of a wave f = v/λ, where v is the velocity of the wave, and λ is the wavelength.

To calculate the wavelength of a microwave light travels through a liquid, it moves at a speed of 2.2 x 10⁸ m/s. If the frecuency of the light wave is 1.1 x 10⁸ Hz, we have to clear λ from the equation f = v/λ:

f = v/λ -------> λ = v/f

λ = 2.2 x 10⁸ m/s / 1.1 x 10⁸ Hz

λ = 2 m (wavelength of the microwave)

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The angle between the two force of magnitude 20N and 15N is 60 degrees (20N force being horizontal) determine the resultant in m
BARSIC [14]

A) The resultant force is 30.4 N at 25.3^{\circ}

B) The resultant force is 18.7 N at 43.9^{\circ}

Explanation:

A)

In order to find the resultant of the two forces, we must resolve each force along the x- and y- direction, and then add the components along each direction to find the components of the resultant.

The two forces are:

F_1 = 20 N at 0^{\circ} above x-axis

F_2 = 15 N at 60^{\circ} above y-axis

Resolving each force:

F_{1x}=F_1 cos \theta = (20)(cos 0)=20 N\\F_{1y}=F_1 sin \theta =(20)(sin 0)=0 N

F_{2x}=F_2 cos \theta = (15)(cos 60)=7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 60)=13.0 N

So, the components of the resultant are:

F_x = F_{1x}+F_{2x}=20+7.5 = 27.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N

And the magnitude of the resultant is:

F=\sqrt{F_x^2+F_y^2}=\sqrt{27.5^2+13.0^2}=30.4 N

And the direction is:

\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{27.5})=25.3^{\circ}

B)

In this case, the 15 N is applied in the opposite direction to the 20 N force. Therefore we need to re-calculate its components, keeping in mind that the angle of the 15 N force this time is

\theta=180^{\circ}-60^{\circ}=120^{\circ}

So we have:

F_{2x}=F_2 cos \theta = (15)(cos 120)=-7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 120)=13.0 N

So, the components of the resultant this time are:

F_x = F_{1x}+F_{2x}=20-7.5 = 12.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N

And the magnitude is:

F=\sqrt{F_x^2+F_y^2}=\sqrt{13.5^2+13.0^2}=18.7 N

And the direction is:

\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{13.5})=43.9^{\circ}

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

7 0
3 years ago
Limestone formations in caves are considered what kind of weathering?
Zanzabum

Answer:

A.

Explanation:

because the carbonic acid reacts to the limestone.

8 0
2 years ago
Two balloons are charged with an identical quantity and type of charge: -0.0025 C. They are held apart at a separation distance
jok3333 [9.3K]

Answer:

F = 878.9 N

Explanation:

The electrostatic force of attraction or repulsion is given by Coulomb's Law as follows:

F = kq₁q₂/r²

where,

F = Force pf repulsion between balloons = ?

k = Coulomb's Constant = 9 x 10⁹ N.m²/C²

q₁ = q₂ = magnitudes of 1st and 2nd charge = 0.0025 C

r = distance between balloons = 8 m

Therefore,

F = (9 x 10⁹ N.m²/C²)(0.0025 C)(0.0025 C)/(8 m)²

<u>F = 878.9 N</u>

3 0
3 years ago
A coin dropped in the lift it takes time 0.5 s to reach the floor when lift is staionary it takes time t when lift is moving up
BARSIC [14]

Answer:

t₁ > t₂

Explanation:

A coin is dropped in a lift. It takes time t₁ to reach the floor when lift is stationary. It takes time t₂ when lift is moving up with constant acceleration. Then t₁ > t₂,  t₁ = t₂,  t₁ >> t₂ ,  t₂ > t₁

Solution:

Newton's law of motion is given by:

s = ut + (1/2)gt²;

where s is the the distance covered, u is initial velocity, g is the acceleration due to gravity and t is the time taken.

u = 0 m/s, t₁ is the time to reach ground when the light is stationary and t₂ is the time to reach ground when the lift is moving with a constant acceleration a.

hence:

When stationary:

s=\frac{1}{2}gt_1^2\\\\t_1^2=\frac{2s}{g}  \\\\When\ moving\ with\ acceleration(a):\\\\s=\frac{1}{2}(g+a)t_2^2\\\\t_2^2=\frac{2s}{g+a}

Hence t₂ < t₁, this means that t₁ > t₂.

4 0
3 years ago
Someone help me please.
Soloha48 [4]

1/2*2.8*x^{2}=2.8*9.81*1.50

X=5.425

Because K.E=1/2*M*V² and it is equal to P.E in the conservation of energy which means its K.E=P.E

P.E=m*g*h

So K.E equals 1/2*2.8*(5.425)²=41.20

8 0
3 years ago
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