Question

Calculate the volume occupied by 25.2 g of co2 at 0.84 atm and 25°c. r = 0.08206 latm/kmol.

Answer 1

Answer:

16.68 L

Explanation:

First of all, we need to calculate the number of moles corresponding to 25.2 g of CO2.

The molar mass of CO2 is 44.01 g/mol, therefore the number of moles is:

$n=\frac{m}{M_m}=\frac{25.2 g}{44.01 g/mol}=0.573 mol$

So now we can use the ideal gas equation:

$pV=nRT$

where:

p = 0.84 atm is the gas pressure

V = ? is the volume

n = 0.573 mol is the number of moles

R = 0.08206 L atm / K mol is the gas constant

T = 25°c = 298 K is the gas temperature

Substituting into the equation and re-arranging it, we find the volume:

$V=\frac{nRT}{p}=\frac{(0.573 mol)(0.08206 Latm/Kmol)(298 K)}{0.84 atm}=16.68 L$