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3 years ago

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Susan is painting serveral rooms in her house . She wants to know the total area of the walls so she can buy enough paint. Estim

ate the total area of the rooms. A. 290m2 B.310m2 C.360m2 D.400m2 please help me

1 answer:

vovikov84 [41]3 years ago

3 0

wouldn't we need to know the width and length of the walls

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at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

#SPJ9

6 0

2 years ago

Read 2 more answers

I don’t know how to do it can someone help me?

frozen [14]

Answer:f(g(0))= 1/5

g(f(0))= 7

Step-by-step explanation:

for f(g(0))=you solve for g(x) but you plug in 0 for x so g(0)= 8(0)+3

=3

so now you plug in the answer of the function of g(x) witch is 3 and plug it in as the x for F(x) so f(3)= 1/(3)+2

= 1/5

so f(g(0)) is equal to 1/5

Now for G(f(0)) you solve for f(x) by pluging 0 for x so F(0)= 1/(0)+2

=1/2

now you plug in 1/2 for the x of g(x) so g(1/2)= 8(1/2)+3

= 4+3

=7

so g(f(0)) is equal to 7

Hope this helps:)

3 0

3 years ago

Graph the line that represents this equation:<br> y = -5.1 +2

Mrac [35]

That's for the equation I got from the picture

4 0

3 years ago

A right triangle has sides of length 3, 4, and .

olchik [2.2K]

Answer:

5/hypotenuse, the square root of 7/ leg

Step-by-step explanation:

3^2+4^2=25 or 5^2. you use a^2+b^2=c^2. it would be one of the hypotenuses. If the missing number is a leg, you would do 4^2=3^2+x^2. 16=9+x^2, 7=x^2, so you plug in the numbers differently.

3 0

3 years ago

Read 2 more answers

A family is driving from Phoenix to San Francisco. On a map grid, Phoenix is located at (–12, –16), and San Francisco is located

makkiz [27]

The answer is 34.05

The total distance (D) is the sum of three distances (d1, d2, and d3).

The distance formula is $d = \sqrt{(x2-x1)^{2} +(y2-y1)^{2}}$

Distance 1: Phoenix (–12, –16) to Blythe (–20, –9)<span>:
</span> $d1 = \sqrt{(-20-(-12))^{2} +(-9-(-16))^{2}} =\sqrt{(-20+12)^{2} +(-9+16)^{2}} \\ =\sqrt{(-8)^{2} +(7)^{2}}= \sqrt{64+49} = \sqrt{113}= 10.63$

Distance 2: Blythe (–20, –9) to Los Angeles (–33, –4):
$d2 = \sqrt{(-33-(-20))^{2} +(-4-(-9))^{2}} =\sqrt{(-33+20)^{2} +(-4+9)^{2}} \\ =\sqrt{(-13)^{2} +(5)^{2}}= \sqrt{169+25} = \sqrt{194}= 13.93$

Distance 3: Los Angeles (–33, –4) to <span>San Francisco (–36, 5)
</span> $d3 = \sqrt{(-36-(-33))^{2} +(5-(-4))^{2}} =\sqrt{(-36+33)^{2} +(5+4)^{2}} \\ =\sqrt{(-3)^{2} +(9)^{2}}= \sqrt{9+81} = \sqrt{90}= 9.49$
<span>
D = d1 + d2 + d3 = 10.63 + 13.93 + 9.49 = 34.05</span>

3 0

3 years ago