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ratelena [41]
3 years ago
9

Just need help with this problem

Mathematics
1 answer:
lawyer [7]3 years ago
4 0
X->inf is the right side of the graph and you can see that y is decreasing. this is represented by option 1.

x->-inf is the left side of the graph and you can see that y is also decreasing. this is represented by option 2.
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Can someone explain to me how to do question number 6 please?
kirill115 [55]
Do the crossing out method. so if it is 2.50 per pound for peaches, try A, 11 pounds. 2.50 times 11 is 27.5, and now we have the rest, 154 pounds as apples so we multiply it by 1.75 which is 269.5, we add them up and we dont get 337.50, so we try out b,  18 times 2.5 is 45 so we still have 147 pounds left for apples, multiply it by 1.75 which is 257.25 and if we add up 45 and 257.25 we dont get 337.5 so now we try c which is 65, multiply it by 2.5 its 162.5 and we have 100 pounds of apples left. we do the same and we get 175, 175 plus 162.5 is 337.5 so C/3 is the correct answer
6 0
3 years ago
If your weight is 150 pounds and your mass is 15.3 kilograms, what would those values be if you were on the moon? The gravitatio
natulia [17]
Weight = mass * g  where g = gravitational force

so a weight of 150 pounds would be 150 / 6 = 25  on the moon.
The mass would be the same as on earth.
3 0
3 years ago
Elizabeth attempts a field goal by kicking a football from the ground with an initial vertical
sammy [17]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf h(t)=-16t^2+64t+0\implies h(t)=-16t^2+64t\implies \stackrel{\textit{hits the ground}~\hfill }{0=-16t^2+64t} \\\\\\ 0=-16t(t-4)\implies t= \begin{cases} 0\\ \boxed{4} \end{cases}

Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.

5 0
3 years ago
WITH PICTURE!!3. What is the value of x in the regular polygon below? (3 points)
monitta

Answer: FIRST OPTION.

Step-by-step explanation:

Regular polygons are those polygons whose sides are equal in length and whose angles are all equal.

By definition each interior angle of a Regular polygon,is:

\frac{180 ( n -2 )}{n}  (In degrees)

Where "n" is the number of sides of the polygon.

Observe the Regular polygon given in the exercise.

Since it has 6 sides, you can conclude that it is an Hexagon. Then:

n=6

Substituting into  \frac{180 ( n -2 )}{n}  and evaluating, you get:

\frac{180 ( 6 -2 )}{6}=120\°

Knowing this, you can write the following equation:

3x=120

Finally, you must solve for "x" in order to find its value. This is:

x=\frac{120}{3}\\\\x=40

8 0
4 years ago
A baby’s t-shirt requires 2/9 yards of fabric. How many t-shirts can be made from 38 yards?
Bess [88]
8 4/9 hope this helps!!!
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3 years ago
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