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erma4kov [3.2K]
4 years ago
14

Can someone please help with this problem and explain. Please answer quickly, thx :) (picture included)

Mathematics
1 answer:
Anna007 [38]4 years ago
3 0
Exponential laws
(x^{m})^{n}=x^{mn}
x^{\frac{m}{n}}=\sqrt[n]{x^{m}}

so
(m^(2/3))^(1/2)=m^(2/3 times 1/2)=m^(2/6)=m^(1/3)= \sqrt[3]{m^{1}}= \sqrt[3]{m}
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The steps on the construction of a segment bisector by paper folding, and label the midpoint M is given below.

<h3>What are the steps of this construction?</h3>

1. First, one need to open a Compass so that it is said to be more than half the length of the said segment.

2. Without altering it, with the aid of the compass, do  draw an art above and also below the said line segment from one of the segment endpoints.

3. Also without altering it and with use the compass, do draw another pair of arts from the other and points. One arc will be seen above the segment and the other or the second arc will be seen below.

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5 0
2 years ago
If the total cost plus shipping is greater than $35,then you receive a 10% discount off the original selling price. Do you quali
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<u>It's not clear what is the specific requirement of the question, but I'll assume a couple of situations to help you with your real problem.</u>

Answer:

$45 (qualified)

$30 (did not qualify)

Step-by-step explanation:

<u>Percentage Calculations</u>

Relative quantities are usually expressed as percentages (%). We say x percent of y is the proportion xy/100. When discounts or surcharges are applied, they are subtracted or added to the original quantity.

The question explains I receive a 10% discount off the original selling price if the total cost plus shipping is greater than $35. Let's assume the total cost plus shipping is $50. Since it's greater than $35, it qualifies for a discount. The discount is 10% of $50 = (10)(50)/100= $5. So the new total cost will be $50 - $5 = $45

Let's suppose now the total cost+shipping is $30. Since it's not greater than $35, no discount will be applied and we have to pay $30

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3 years ago
Please help i need help
lora16 [44]

Answer:

yes you hrlp me thank you so much

7 0
3 years ago
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