Can someone please help with this problem and explain. Please answer quickly, thx :) (picture included)

Mathematics

1 answer:

Anna007 [38]3 years ago

3 0

Exponential laws
$(x^{m})^{n}=x^{mn}$
$x^{\frac{m}{n}}=\sqrt[n]{x^{m}}$

so
(m^(2/3))^(1/2)=m^(2/3 times 1/2)=m^(2/6)=m^(1/3)= $\sqrt[3]{m^{1}}$ = $\sqrt[3]{m}$

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Let x be the probability of winning and let y be the probability of losing. Then we can write the following equation:
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