Question

two times the least of three consecutive odd integers exceeds three times the greatest by 25. what are the integers?

Answer 1

$2(2n+1)=3(2n+5)+25\\ 4n+2=6n+15+25\\ 2n=-38\\ n=-19\\\\ 2n+1=2\cdot(-19)+1=-37\\ 2n+3=2\cdot(-19)+3=-35\\ 2n+5=2\cdot(-19)+5=-33\\\\ \boxed{-37,-35,-33}$