two times the least of three consecutive odd integers exceeds three times the greatest by 25. what are the integers?

1 answer:

6 0

$2(2n+1)=3(2n+5)+25\\
4n+2=6n+15+25\\
2n=-38\\
n=-19\\\\
2n+1=2\cdot(-19)+1=-37\\
2n+3=2\cdot(-19)+3=-35\\
2n+5=2\cdot(-19)+5=-33\\\\
\boxed{-37,-35,-33}$

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