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3 years ago

Evaluate the expression for w = 1. 14w = ?

Mathematics

1 answer:

bekas [8.4K]3 years ago

3 0

Answer:

what does w mean and are you trying to find how many days

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What is the range of the function on the graph

meriva

Answer:

Y ≤ 3

Step-by-step explanation:

The Domain is the x values the function holds, while the range is the y values the function holds. This means that, looking at the graph, the range of the function is all y values less than or equal to 3, or Y ≤ 3.

4 0

4 years ago

Read 2 more answers

3y''-6y'+6y=e*x sexcx

Simora [160]

From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

$3r^2-6r+6=0\iff r^2-2r+2=0$

which has roots at $r=1\pm i$ . This admits the two fundamental solutions

$y_1=e^x\cos x$
$y_2=e^x\sin x$

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the fundamental solutions. We have

$W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}$

and so

$u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx$
$u_1=\dfrac13\ln|\cos x|$

$u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx$
$u_2=\dfrac13x$

Therefore the particular solution is

$y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

so that the general solution to the ODE is

$y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

7 0

3 years ago

Cual es la relacion entre <a y <b?

RideAnS [48]

Answer:

Angulos suplementarios

7 0

3 years ago

Suppose you want to know how fast you traveled from the park to the library. As you moved, your speed varied from second to seco

frutty [35]

Step-by-step explanation:

In order to describe speed of an object, we must describe the average speed of the entire trip. It is equal to the distance moved divided by time taken.

If a person covers a distance of 1 km to the library in 15 minutes, we can find its average speed.

Firstly, we convert 15 minutes to hour, 15 min = 0.25 hours

Now, using formula of speed = distance/time

$v=\dfrac{1\ km}{0.25\ h}\\\\v=4\ km/h$

It means that the average speed of the person is 4 km/h. Hence, the given statement is true.

6 0

3 years ago

The weights of dogs at a kennel are Normally distributed with a mean of 18 pounds and a standard deviation of 3.5 pounds.In whic

Ierofanga [76]

Answer:

P(x=25)=P(z=2)=0.9972 or 99.72%

Step-by-step explanation:

Mean = 18 pounds

Standard Deviation = 3.5 pounds

x= 25

We need to find P(x=25)

First, we need to find z-score using formula: $z-score=\frac{x-\mu}{\sigma}$

Finding z-score when x=25

$z-score=\frac{x-\mu}{\sigma}\\z-score=\frac{25-18}{3.5}\\z-score=2$

So, we need to find P(z=2)=P(x=25)

Looking at z-score table we can find P(z=2)

P(z=2)=0.9972 or 99.72%

So, P(z=2)=0.9972 or 99.72%

3 0

3 years ago

Read 2 more answers