Just say in the store hahaha bfebfefbevfwvtvt2vt2vt3v3t3bt3btt3tbt2b
Let x represent amount invested in the higher-yielding account.
We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be
.
We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.
, where,
I = Amount of interest,
P = Principal amount,
r = Annual interest rate in decimal form,
t = Time in years.
We are told that interest rates are 6% and 10%.


Amount of interest earned from lower-yielding account:
.
Amount of interest earned from higher-yielding account:
.

Let us solve for x.



Therefore, the man invested $30,000 at 10%.
Amount invested in the lower-yielding account would be
.
Therefore, the man invested $60,000 at 6%.
Answer:
34 is 20
35 is 82
Step-by-step explanation:
Answer:
there are 3.3399 moles in 318 grams! ✔️
Step-by-step explanation:
So we know that 100 grams MgCl2 to mol = 1.0503 mol.
Therefore, to find the number of moles in 318g of the compound, we use the rule of three:
if 1.0503 mol -------------> 100 grams
X <------------- 318 grams
The solution is: X = (318*1.0503)/100 = 3.3399 mol.
Summarizing, there are 3.3399 moles in 318 grams! ✔️