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maxonik [38]
3 years ago
13

How do you read a line pointu

Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0
By making a line plot you first make a frequency table then you make the line plot
but with fractions u dont make a frequency table you just ordedr the fractions least to greatest i think

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PLEASE HELP!!
olga_2 [115]

The value of a = 2.17 and b = 1.95.

<h3>What is regression line?</h3>

A regression line is a graphic representation of the regression equation expressing the hypothesized relationship between an outcome or dependent variable and one or more predictors or independent variables;

y=2.01*1.93^{x}

Correlation:

r=0.964

R-squared:

r²=0.9292

Hence, value of a and b is 2.17 and 1.95.

learn more about regression line here:

brainly.com/question/11340674

#SPJ1

8 0
2 years ago
What is 5 13.5% of ?​
Alekssandra [29.7K]

Answer:

67.5

Step-by-step explanation:

Okay so I spent way to long overthinking this problem but in the end, I just used common sense to figure this one out. *it still may be wrong though...

A way to check if this is correct is dividing 67.5 by 5 and it equals to 13.5 which should make that answer correct?

4 0
3 years ago
Read 2 more answers
The box plots below show student grades on the most recent exam compared to overall grades in the class:
svetlana [45]
<span>he box plots below show attendance at a local movie theater and high school basketball games: two box plots shown. The top one is labeled Movies. Minimum at 60, Q1 at 65, median at 95, Q3 at 125, maximum at 150. The bottom box plot is labeled Basketball games. Minimum at 90, Q1 at 95, median at 125, Q3 at 145, maximum at 150. Which of the following best describes how to measure the spread of the data? The IQR is a better measure of spread for movies than it is for basketball games. The standard deviation is a better measure of spread for movies than it is for basketball games. The IQR is the best measurement of spread for games and movies. The standard deviation is the best measurement of spread for games and movies.</span>

7 0
3 years ago
Read 2 more answers
The situation is as follows: Smart phones have changed the world and how we spend our time. A group of researchers at BYU want t
Scilla [17]

Answer:

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

Step-by-step explanation:

Confidence interval normal

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.96}{2} = 0.02

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.02 = 0.98, so Z = 2.054.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.054\frac{54}{\sqrt{430}} = 5.35

The lower end of the interval is the sample mean subtracted by M. So it is 312 - 5.35 = 306.65 minutes

The upper end of the interval is the sample mean added to M. So it is 312 + 5.35 = 317.35 minutes

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

8 0
3 years ago
Mama's Italian Restaurant has collected data about customer sauce orders. It calculated that P(marinara) = 0.82, P(alfredo) = 0.
Keith_Richards [23]
P ( m ) = 0.82
P ( a ) = 0.76
P ( m or a ) = 0.96
P ( m and a ) = ?
--------------------------
P ( m or a ) = P ( m ) + P ( a ) - P ( m and a )
P ( m and a ) = P ( m ) + P ( a ) - P ( m or a ) =
= 0.82 + 0.76 - 0.96 = 0.62
Answer: P ( marinara and alfredo ) = 0.62
7 0
3 years ago
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