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3 years ago

How do you read a line pointu

1 answer:

5 0

By making a line plot you first make a frequency table then you make the line plot
but with fractions u dont make a frequency table you just ordedr the fractions least to greatest i think

You might be interested in

Which fraction represents the decimal 0.8888...?

suter [353]

Answer: The decimal 0.88888.... represented by the fraction $\dfrac{8}{9}$

Step-by-step explanation:

Since we have given that

0.888888....

So, Let x = 0.88888....= $0.\bar{8}$ -----(1)

Now, multiply by 10 on both sides, we get that

$10x=8.8888.....=8.\bar{8}----------(2)$

Now, Subtracting (1) from (2), we get that

$10x-x=8.\bar{8}-0.\bar{8}\\\\9x=8\\\\x=\dfrac{8}{9}$

Hence, the decimal 0.88888.... represented by the fraction $\dfrac{8}{9}$

8 0

3 years ago

Read 2 more answers

What is the value of -17 - (-1) + 2/3 + -1/2?

netineya [11]

Answer:

-95/6 or -15.83 repeating

Step-by-step explanation:

6 0

3 years ago

Help me please answer all because idk if I was correct scientific notation

valentina_108 [34]

Answer:

I think the first 4 are right

5-8

sorry I cant read it it it is too small so I will explain

5.1 x 10^-2 would be 0.051 just move the decimal left x spaces where x is the exponent

4.4 x 10^3

7.5 x 10^4

6.99 x 10^7

5.75 x 10^9

8.4 x 10^-2

9.9 x 10^-3

5.15 x 10^-7

3.07 x 10^-5

you got it right

Singapore

Luxembourg

Australia

Egypt

Brazil

3,670,000,000

6.2 x 10^-6

125,000,000,000

1.25 x 10^11

Step-by-step explanation:

i hope I helped

3 0

3 years ago

Michael paid $11.48 for sliced cheese at the deli counter. The cheese cost $3.28 per pound. How much cheese did he buy?

Charra [1.4K]

Michael bought 3.5 lbs of cheese

Divide 11.48 by 3.28

3 0

3 years ago

Read 2 more answers

A gondola (cable car) at a ski area holds 50 people. Its maximum safe load is 10000 pounds. A population of skiers has a distrib

fenix001 [56]

Answer: 0.03855

Step-by-step explanation:

Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.

Its maximum safe load is 10000 pounds.

Let X denotes the weight of 50 people.

As per given ,

Population mean weight of 50 people = $\mu=50\times190=9500\text{ pounds}$

Standard deviation of 50 people $=\sigma=40\sqrt{50}=40(7.07106781187)=282.84$

Then , the probability its maximum safe load will be exceeded =

$P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855$

Thus , the probability its maximum safe load will be exceeded = 0.03855

3 0

3 years ago