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maxonik [38]
3 years ago
13

How do you read a line pointu

Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0
By making a line plot you first make a frequency table then you make the line plot
but with fractions u dont make a frequency table you just ordedr the fractions least to greatest i think

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Which fraction represents the decimal 0.8888...?
suter [353]

Answer: The decimal 0.88888.... represented by the fraction \dfrac{8}{9}

Step-by-step explanation:

Since we have given that

0.888888....

So, Let x = 0.88888....=0.\bar{8} -----(1)

Now, multiply by 10 on both sides, we get that

10x=8.8888.....=8.\bar{8}----------(2)

Now, Subtracting (1) from (2), we get that

10x-x=8.\bar{8}-0.\bar{8}\\\\9x=8\\\\x=\dfrac{8}{9}

Hence, the decimal 0.88888.... represented by the fraction \dfrac{8}{9}

8 0
2 years ago
Read 2 more answers
What is the value of -17 - (-1) + 2/3 + -1/2?
netineya [11]

Answer:

-95/6 or -15.83 repeating

Step-by-step explanation:

6 0
3 years ago
Help me please answer all because idk if I was correct scientific notation
valentina_108 [34]

Answer:

I think the first 4 are right

5-8

sorry I cant read it it it is too small so I will explain

5.1 x 10^-2 would be 0.051 just move the decimal left x spaces where x is the exponent

9

4.4 x 10^3

10

7.5 x 10^4

11

6.99 x 10^7

12

5.75 x 10^9

13

8.4 x 10^-2

14

9.9 x 10^-3

15

5.15 x 10^-7

16

3.07 x 10^-5

17

you got it right

18

you got it right

19

Singapore

Luxembourg

Australia

Egypt

Brazil

20

3,670,000,000

21

6.2 x 10^-6

22

125,000,000,000

1.25 x 10^11

Step-by-step explanation:

i hope I helped

3 0
3 years ago
Michael paid $11.48 for sliced cheese at the deli counter. The cheese cost $3.28 per pound. How much cheese did he buy?
Charra [1.4K]
Michael bought 3.5 lbs of cheese 

Divide 11.48 by 3.28
3 0
2 years ago
Read 2 more answers
A gondola (cable car) at a ski area holds 50 people. Its maximum safe load is 10000 pounds. A population of skiers has a distrib
fenix001 [56]

Answer:   0.03855

Step-by-step explanation:

Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.

Its maximum safe load is 10000 pounds.

Let X denotes the weight of 50 people.

As per given ,

Population mean weight of 50 people = \mu=50\times190=9500\text{ pounds}

Standard deviation of 50 people =\sigma=40\sqrt{50}=40(7.07106781187)=282.84

Then , the probability its maximum safe load will be exceeded =

P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855

Thus , the probability its maximum safe load will be exceeded = 0.03855

3 0
3 years ago
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