Answer:
d. (8)
Step-by-step explanation:
3 = √(x + 1)
3 = √(8 + 1)
3 = √9
3 = 3
Answer:
2 7/15
Step-by-step explanation:
37/15 or 2 7/15
The question is:
Check whether the function:
y = [cos(2x)]/x
is a solution of
xy' + y = -2sin(2x)
with the initial condition y(π/4) = 0
Answer:
To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.
Let us do that.
y = [cos(2x)]/x
y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]
Now,
xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x
= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)
= -2sin(2x)
Which is the right hand side of the differential equation.
Hence, y is a solution to the differential equation.
Answer:
Correct answer: t₂ = 70 minutes
Step-by-step explanation:
Given:
t₁ = 28 minutes and t₁₂ = 20 minutes, t₂ = ?
The necessary equation for this situation is:
1/t₁ + 1/t₂ = 1/t₁₂ => 1/28 + 1/t₂ = 1/20 => (28 + t₂)/ 28 t₂ = 1/20 =>
28 t₂ = (28 + t₂) · 20 = 20 t₂ + 560 => 28 t₂ - 20 t₂ = 560 =>
8 t₂ = 560 => t₂ = 560/8 = 70 minutes
t₂ = 70 minutes
God is with you!!!
