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shusha [124]
3 years ago
8

Why the systems must have the same solution?system(a)4x-5y=13.....3x+6y=11........system(b) 8x-10y=26.....x-11y=2.........AKA QU

ESTION 3

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
3 0
When you add the equations in (a) you get 7x+y=24.

When you subtract the equations in (b) you also get 7x+y=24.

That means to solve both systems you can work with the same equation. However that is not enough. We must have two equivalent equations. We found only one.

Notice however that in the (b) we can take the first equation and divide every term by 2. When we do this we get 4x-5y=13. That’s the first equation in (a).

So both systems can be solved by working with the same two equations. These are 5x-5y=13 and 7x+y=24. And since we have two equations and two unknowns (the number of equations matches the number of variables) there is only one solution — one x and y that would make both systems true — solve both systems.

Basically we showed the systems are equivalent!
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After a 16% increase the price of a pair of running shoes was $40.60. What was the old price of the shoes
Delvig [45]

Answer:

34.10

Step-by-step explanation:

Note:

16% = .16

Important:

What was the <u>old price</u> of the shoes

Solution:

40.60 x .16 = 6.946 [Round:6.50]

40.60-6.50= 34.10

Hence, the old price of the shoes is $34.10

5 0
2 years ago
3. The following sets are not equal - An (BUC) and AU(BnC) Construct a universe U and non-empty sets A, B, and C so that the abo
yarga [219]

Answer:

1.U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

2.U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

Step-by-step explanation:

We are given that A\cap (B\cup C) and A\cup (B\cap C)

are different sets

1.We have to construct a universe set U and non empty sets A,B and C so that above set in fact the same

Suppose U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

B\cap C=\phi

B\cup C={2,3,4,5}

A\cap (B\cup C)={2}\cap{2,3,4,5}={2}

A\cup (B\cap C)={2}\cup\phi={2}

Hence, A\cap (B\cup C)=A\cup (B\cap C)

2.We have to construct a universe set U and non empty sets A,B and C so that  above sets are in fact different

Suppose U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

B\cap C=\phi

B\cup C={2,3,4}

A\cup (B\cap C)={1,2}\cup \phi={1,2}

A\cap (B\cup C)={1,2}\cap {2,3,4}={2}

Hence, A\cap (B\cup C)\neq A\cup (B\cap C)

3 0
3 years ago
Does anyone know what 8x1/6 is?
mario62 [17]
Answer: 1.333333333333333333334
5 0
3 years ago
Read 2 more answers
I need help with everything.
LekaFEV [45]

Step-by-step explanation:

5. 102 = 6( 1 + 4p)

102 = 6 + 24p

102 - 6 = 24p

96 = 24p

96/ 24 = p

4 = p

5 0
3 years ago
Find the length of a rectangle whose area=320²cm and breadth=16cm​
soldier1979 [14.2K]

Answer:

20

Step-by-step explanation:

area = length * breadth

320cm² = length * 16cm

divide both sides by 16cm to isolate length

20cm = length

6 0
3 years ago
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