Answer:
Option 1, 2, 5
Explanation:
Options for the question
- car a and car b are both moving toward the origin.
- car a and car b are moving in opposite directions.
- car a is moving faster than car b.
- car a and car b started at the same location.
- car a and car b pass each other at the crossover point on the graph. time (s)
Solution -
The motion of any object is represented by position-time In such graphs the position of an object is fixed for any starting point on the y-axis and time on the x-axis.
The slope of such curves determine the velocity of the object at all its position within the graph. The steeper the slope is, the faster the the object is moving.
Hence, the following statements are correct
Option 1, 2, 5
Answer:
1. are heterozygous for the disease.
Explanation:
<em>Since the disease causes the death of chicks before hatching, it means that those with the disease cannot be found in the population. In order for the allele of the disease to be passed from generation to generation, there must be parent birds that are carrying the disease in heterozygous state.</em>
Option 1 is the correct option.
Answer:
<em>Trichomonas vaginalis</em>
Explanation:
<em>Trichomonas vaginalis</em> is a protozoan parasite that causes Trichomonasis.This STD caused by this one-cell organism, is one of the most common infections transmitted sexually.It usually affects the genitourinary tract of both males and females.
Most males who are infected by this parasite hardly know they are being infected by it. Men are typically asymptomatic. But symptoms such as enlarged prostate gland, urethritis, or epididymitis often present themselves later in males.
The green house effect is a natural process that warms the Earth surface.
((Carbon dioxide))
Answer:
Let:
Y = Yellow R = Round
y = green r = Wrinkled
If you look at the F1 generation, all the plants are round and yellow, so these are the dominant traits and each offspring is heterozygous for both traits. The cross for the F2 generation would then be:
<em>YyRr x YyRr</em>
In a Punnett it would look like the attached picture.
For the forked-line diagram, first you will need to know the gentypes and ratio of each trait in a monohybrid cross. Select one trait, and then branch each gentype to the next trait, linking it with each possible genotype combination of the monohybrid cross.
Attached is a picture of the Forked Branch diagram for this cross.
