4 years ago

Make perfect square V^2 + 8v +

1 answer:

6 0

If you're asking for the final term, the solution is to take b(from ax^2+bx+c), half it, and then square it. So in this case, b is 8.
8/2=4
4^2=16
So:
v^2+8v+16
If you factor it, it becomes (v+4)^2, which shows that its a perfect square.

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