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4 years ago

12

Make perfect square V^2 + 8v +

1 answer:

Yuri [45]4 years ago

6 0

If you're asking for the final term, the solution is to take b(from ax^2+bx+c), half it, and then square it. So in this case, b is 8.
8/2=4
4^2=16
So:
v^2+8v+16
If you factor it, it becomes (v+4)^2, which shows that its a perfect square.

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Is this equation a direct variation? Y= 4x + 9

Ket [755]

No it wouldn't because a direct variation is in a y=kx formula. That equation shown above is in a y=mx+b format,which is a formula for slope intercept form

8 0

3 years ago

Please help, I’ve got 10 minutes left till I have to hand it in.

Tatiana [17]

Answer:

<h3>2816 is math term of sequence.</h3>

Step-by-step explanation:

$\rm\large\blue{\underline{Given:-}}$

◉ First four term of a sequence 11,22,44,88...

$\rm\large\blue{\underline{To\:Find:}}$

◉ Ninth term of the sequence.

$\Large\texttt\red{\underline{Required\:Solution:}}$

Now first we have to continue the sequence.

11, 22, 44, 88, 176, 352, 704, 1408,

2816, 5632.......

<h3>Hence, 2816 is the Ninth term </h3><h3>of sequence.</h3>

─━─━─━─━─━─━─━─━─━─━─━─

7 0

3 years ago

Determine the function which corresponds to the given graph. (3 points) a natural logarithmic function crossing the x axis at ne

quester [9]

Answer:

$y =log_e(x+3)$

Step-by-step explanation:

It is given that the graph corresponds to a natural logarithmic function.

That means, the function $y$ has a natural log (Log with base $e$ ) of some terms of x.

It is given that asymptote of given curve is at $x= -3$ . i.e. when we put value

$x= -3$ , the function will have a value $y \rightarrow \infty$ .

We know that natural log of 0 is not defined.

So, we can say the following:

$log_e(x+a)$ is not defined at $x= -3$

$\Rightarrow x+a =0\\\Rightarrow x = -a$

i.e. $x =-a$ is the point where $y \rightarrow \infty$

a = 3

Hence, the function becomes:

$y =log_e(x+3)$

Also, given that the graph crosses x axis at x = -2

When we put x = -2 in the function:

$y =log_e(-2+3) = log_e(1) = 0$

And y axis at 1.

Put x = 0, we should get y = 1

$y =log_e(0+3) = log_e(3) \approx 1$

So, the function is: $y =log_e(x+3)$

4 0

4 years ago

Match the mathematical term with the correct definition.

vladimir1956 [14]

.............................

6 0

4 years ago

I need help with question 8 please

leonid [27]

Answer:

38

Step-by-step explanation:

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4 years ago

Read 2 more answers