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3 years ago

Match the mathematical term with the correct definition.

Mathematics

1 answer:

vladimir1956 [14]3 years ago

6 0

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I need help with questions number seven and ten. <br> Answering will give you 28 pts

Anika [276]

Answer:

#7=A

#10=

Step-by-step explanation:

for #10 idk the answer but its kind of similar to number 7

sorry

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3 years ago

Non examples of graphs

Kipish [7]

A Non-example is like there we not enough to grapha

5 0

3 years ago

Read 2 more answers

PHYSICS As a ray of light meets a mirror, the light

Lady bird [3.3K]

<h3>Answer: 37 degrees</h3>

========================================================

Explanation:

The angle of incidence is equal to the angle of reflection. The angle of light coming in is the same as the angle of light bouncing out. Each angle is made with the dashed line as the diagram shows.

So angle RMI = 106 is bisected, i.e. divided in half, to get

Angle RMN = 53
Angle NMI = 53

since 106/2 = 53

Then notice that the horizontal dashed line is perpendicular to the vertical mirror. This means angle NMJ is a 90 degree angle and,

angle RMJ = (angle NMJ) - (angle RMN)

angle RMJ = 90 - 53

angle RMJ = 37 degrees

----------

In short: divide 106 in half to get 53, then subtract it from 90

5 0

2 years ago

ANSWER MY QUESTION PLEASE

mina [271]

When you plug the equation into a graphing calculator the x-intercept is -5
Or you can set the equation equal to 0 and solve for x.

6 0

3 years ago

Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position

Alenkinab [10]

Answer:

$\cos \theta=-\dfrac{8}{17}$

Step-by-step explanation:

Coordinates of Point b $=(-8,15)$

b lies on the circle whose equation is $x^2+y^2=289$

$x^2+y^2=17^2$

Comparing with the general form a circle with center at the origin: $x^2+y^2=r^2$

The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.

For an angle drawn in standard position through point b,

x=-8 which is negative

y=15 which is positive

Therefore, the angle is in Quadrant II.

$\cos \theta=\dfrac{Adjacent}{Hypotenuse} \\$Adjacent=-8\\Hypotenuse=17\\\cos \theta=\dfrac{-8}{17} \\\cos \theta=-\dfrac{8}{17}$

8 0

3 years ago