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Nikitich [7]
3 years ago
6

Write the rule to describe this transformation. Need help please!

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
7 0

Answer:

Figure P'Q'R'S' has been dilated by a scale factor = 1.5 to form image quadrilateral P"Q"R"S".

Step-by-step explanation:

From the graph attached,

Coordinates of point T' → (2, -2)

Coordinates of point T'' → (3, -3)

As it's clear form the picture, quadrilateral P'Q'R'S' has been dilated to form the image quadrilateral P"Q"R"S" by a scale factor = k

By the rule,

T'(x, y) → T"(kx, ky)

Therefore, T'(2, -2) → T"(2k, -2k)

T"(2k, -2k) → T"(3, -3)

By comparing x-coordinates,

2k = 3

k = \frac{3}{2}

k = 1.5

Therefore, figure P'Q'R'S' has been dilated by a scale factor = 1.5 to form quadrilateral P"Q"R"S".

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Given:

The length of the rectangle = 16 ft

The width of the rectangle = 12 ft

The diameter of the semicircle = 12 ft

To find the area of the given figure.

Formula

  • A=A_{1} +A_{2}

where,

A be the area of the given figure

A_{1} be the area of the rectangle

A_{2} be the area of the semicircle.

  • The area of the rectangle = lb where, l be the length and b be the width
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Now,

The radius of the semicircle r = 6 ft

Putting, r=6, l=16 and b= 12 we get,

A_{1} = (16)(12) sq ft

or, A_{1} = 192 sq ft

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or, A_{2}=56.52 sq ft

So,

A = 56.52+192 sq ft

A = 248.52 sq ft

Rounding off to the nearest tenth, we get;

A=248.5 sq ft.

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The area of the composite figure is 248.5 sq ft.

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