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lakkis [162]
2 years ago
15

Sarah needs to make a cake and some cookies. The cake requires 3/4 cups of sugar and the cookies require 3/5 cups of sugar. If s

he has 15/16 cups of sugar does she have enough?
Mathematics
1 answer:
Ann [662]2 years ago
3 0

Answer:No, she does not have enough cups of sugar

Step-by-step explanation:

Sarah needs to make a cake and some cookies. The cake requires 3/4 cups of sugar. If she has 15/16 cups of sugar, then the number of cups of sugar that would be left after making the cake would be

15/16 - 3/4 = (15 - 12)/16 = 1/4

If the cookies require 3/5 cups of sugar, then the cups of sugar that she has won't be enough because

1/4 - 3/5 = (5 - 12)/5 = -7/5 cups

It means that she would need more cups of sugar.

You might be interested in
40.51x+12.45y=666.64
irga5000 [103]

Answer:

The graph of the equation 40.51x+12.45y=666.64 is attached with the answer where the horizontal axis represents the X axis and the vertical axis represents Y axis.

To plot the graph physically just find two points lying on the line. Mark the points on the graph sheet and then join them. This will give you the line represented by the equation.

To find points on the line assume the value of any one variable, substitute it in the equation, then solve the equation to find the value of other variable. For example : assume y = 1; substitute the value of y in the equation;

⇒ 40.51x + 12.45×1 = 666.64

⇒ 40.51x = 666.64 - 12.45

⇒ 40.51x = 654.19

⇒ x = \frac{654.19}{40.51}

⇒ x ≈ 16.149

Therefore point ( 16.149 , 1 ) lie on the graph of the equation.

***Only two points are required to plot this graph just because it represents a straight line, that we can conclude just by observing the equation. If in an equation the power of x is 1 or 0 and power of y is 1 or 0 then only it will represent a straight line in 2-D plane.***

5 0
3 years ago
PLEASE HELP WITH MATH CONSTRUCTED RESPONSE!!
strojnjashka [21]

Answer:

  1. y = 0.937976x +12.765
  2. $12,765
  3. $31,524
  4. the cost increase each year

Step-by-step explanation:

1. For this sort of question a graphing calculator or spreadsheet are suitable tools. The attached shows the linear regression line to have the equation ...

... y = 0.937976x + 12.765

where x is years since 2000, and y is average tuition cost in thousands.

2. The y-intercept is the year-2000 tuition: $12,765.

3. Evaluating the formula for x=20 gives y ≈ 31.524, so the year-2020 tuition is expected to be $31,524.

4. The slope is the rate of change of tuition with respect to number of years. It is the average increase per year (in thousands). It amounts to about $938 per year.

5. [not a math question]

5 0
3 years ago
How many ways are there to select 12 countries in the United Nations to serve on a council if 3 are selected from a block of 45,
sattari [20]

Answer: There are 2346953264 ways to do so.

Step-by-step explanation:

Since we have given that

Total number of selected countries = 12

Number of selected countries from a block of 45 = 3

Number of selected countries from a block of 57 = 4

So, remaining number of selected countries from a block of 69.

So, 12-(3+4)=12-7=5

Now, we need to find the number of ways, so we will use "Combination" to select that number of countries.

So, it becomes.

^{45}C_3\times ^{57}C_4\times ^{57}C_5\\\\=14190\times 395010\times 4187106\\\\=2346953264

Hence, there are 2346953264 ways to do so.

8 0
3 years ago
Find general solutions of the differential equation. Primes denote derivatives with respect to x.
zepelin [54]

Answer:

\mathbf{3x^2y^3+2xy^4=C}

Step-by-step explanation:

From the differential equation given:

6xy^3 +2y ^4 +(9x^2y^2+8xy^3) y' = 0

The equation above can be re-written as:

6xy^3 +2y^4 +(9x^2y^2+8xy^3)\dfrac{dy}{dx}=0

(6xy^3 +2y^4)dx +(9x^2y^2+8xy^3)dy=0

Let assume that if function M(x,y) and N(x,y) are continuous and have continuous first-order partial derivatives.

Then;

M(x,y) dx + N (x,y)dy = 0; this is exact in R if and only if:

\dfrac{{\partial M }}{{\partial y }}= \dfrac{\partial N}{\partial  x}}} \ \ \text{at each point of R}

relating with equation M(x,y)dx + N(x,y) dy = 0

Then;

M(x,y) = 6xy^3 +2y^4\  and \ N(x,y) = 9x^2 y^2 +8xy^3

So;

\dfrac{\partial M}{\partial y }= 18xy^3 +8y^3

       \dfrac{\partial N}{\partial y }

Let's Integrate \dfrac{\partial F}{\partial x}= M(x,y) with respect to x

Then;

F(x,y) = \int (6xy^3 +2y^4) \ dx

F(x,y) = 3x^2 y^3 +2xy^4 +g(y)

Now, we will have to differentiate the above equation with respect to y and set \dfrac{\partial F}{\partial x}= N(x,y); we have:

\dfrac{\partial F}{\partial y} = \dfrac{\partial}{\partial y } (3x^2y^3+2xy^4+g(y)) \\ \\ = 9x^2y^2 +8xy^3 +g'(y) \\ \\ 9x^2y^2 +8xy^3 +g'(y) =9x^2y^2 +8xy^3 \\ \\ g'(y) = 0  \\ \\ g(y) = C_1

Hence, F(x,y) = 3x^2y^3 +2xy^4 +g(y)  \\ \\ F(x,y) = 3x^2y^3 + 2xy^4 +C_1

Finally; the general solution to the equation is:

\mathbf{3x^2y^3+2xy^4=C}

5 0
2 years ago
The class decides to make chocolate chip cookies for Ms. Zagars first day of school in September. Each student needs 3/4 of a st
JulsSmile [24]

Answer:

That'll be 10.5 sticks

6 0
2 years ago
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