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Citrus2011 [14]
3 years ago
5

Imagine that two charged objects are the system of interest. When the objects are infinitely far from each other, the electric p

otential energy of the system is zero. When the objects are close to each other, the electric potential energy is positive. Which of the following statements is(are) incorrect
(a) Both objects are positively charged.
(b) Both objects are negatively charged.
(c) One object is negatively charged and the other one is positively charged.
Physics
1 answer:
podryga [215]3 years ago
5 0

Answer: Option (c) is the correct answer.

Explanation:

It is known that the expression for potential energy related to charges and distance between their separation is as follows.

           U_{q} = \frac{kq_{1}q_{2}}{r}  

where,   q_{1} and q_{2} are two charges

                r = distance of separation between the charges

               k = electrostatic constant

So, when both the charges are carry the same charge and r is small then the value of potential energy will be positive in nature.

Whereas if the distance of separation between the charges is infinitely large then the potential energy calculated will be zero everywhere.

Thus, we can conclude that the statement one object is negatively charged and the other one is positively charged, is incorrect.

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nignag [31]

Answer:

D.) independent variable on the x-axis

Explanation:

Normally in an x-y plane, the value of x is taken as an independent variable, i.e. it is independent because it can assume any value (real number), while y depends on the value x. for example for the following equation.

y = x

Where:

x = independent value.

y = dependent value of x

This is the equation of a line, inclined with slope equal to 1.

4 0
3 years ago
An alternative to CFL bulbs and incandescent bulbs are light-emitting diode (LED) bulbs. A 16-W LED bulb can replace a 100-W inc
Yanka [14]

Answer:

LED bulb = 0.145 A

Incandescent bulb = 0.909 A

CFL bulb = 0.218 A

Explanation:

Given:

Power rating of LED bulb (P₁) = 16 W

Power rating of incandescent bulb (P₂) = 100 W

Power rating of CFL bulb (P₃) = 24 W

Terminal voltage across the circuit (V) = 110 V

We know that, power is related to terminal voltage and current drawn as:

P=VI

Express this in terms of 'I'. This gives,

I=\frac{P}{V}

Now, calculate the current drawn in each bulb using their respective values.

For LED bulb, P_1=16\ W, V=110\ V

So, current drawn is given as:

I_1=\frac{16\ W}{110\ V}=0.145\ A

For incandescent bulb, P_2=100\ W, V=110\ V

So, current drawn is given as:

I_2=\frac{100\ W}{110\ V}=0.909\ A

For CFL bulb, P_3=24\ W, V=110\ V

So, current drawn is given as:

I_3=\frac{24\ W}{110\ V}=0.218\ A

Therefore, the currents drawn through LED bulb, incandescent bulb and CFL bulb are 0.145 A, 0.909 A and 0.218 A respectively.

5 0
4 years ago
There are four springs stretched by the same mass. Spring A stretches 25 cm. Spring B stretches
juin [17]

Answer:

Spring C

Explanation:

According to Hooke's law, a force require to compress or extend a spring is directly proportional to the distance from its mean position.

The force of compression or expansion of the spring is given by the formula,

                                      F = k x

Where,

                   k - spring constant. It is the constant value of the particular spring

                   x - distance of expansion or compression from mean position.

The x value of different spring,

                    A = 25 cm

                     B = 10 cm

                     C = 100 cm

                     D = 1 cm

The highest value of x for the same mass has the smallest spring constant according to the equation.

Hence, C has the smallest spring constant.

7 0
3 years ago
An object becomes positively charged when it
goldfiish [28.3K]

Answer:

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5 0
3 years ago
Read 2 more answers
Ron weighs a bottle with a mass of 0.5 kilograms on a spring scale. The spring stretches by 1 centimeter. He then weighs a secon
Yuri [45]

Answer:

1 kg

Explanation:

Applying,

Hook's law,

F = ke................. Equation 1

Where F = force, k = force constant of the spring, e = extension.

But from the question,

The weight of the bottle is the force acting on the spring scale

therefore,

mg = ke............ Equation 2

Where m = mass of the bottle, g = acceleration due to gravity.

make k the subject of the equation

k = mg/e............ Equation 3

Given: m = 0.5 kg, e = 1 cm = 0.01 m

Constant: g = 9.8 m/s²

k = (0.5×9.8)/0.01

k = 490 N/m

If the mass of the second bottle is weighed,

given: e = 2 cm = 0.02 m

subtitute into equation 1

m×9.8 = 490×0.02

9.8m = 9.8

m = 9.8/9.8

m = 1 kg.

Hence the mass of the second bottle is 1 kg

5 0
3 years ago
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