Answer:
The force of gravity is not the same as being on the earth. when your on the earth there no gravitational pull its all up to the air
Explanation:
No explanation
When you double capacitance and inductance, the new resonance frequency becomes f/2.
The resonance frequency of RLC series circuit, is the frequency at which the capacity reactance is equal to inductive reactance.
It can also be defined as the natural frequency of an object where it tends to vibrate at a higher amplitude.
Xc = Xl
which gives the value for resonance frequency:

where;
f is the resonance frequency
L is the inductance
C is the capacitance
When you double capacitance and inductance, the new resonance frequency becomes;




Thus from above,
When you double capacitance and inductance, the new resonance frequency becomes f/2.
Learn more about resonance frequency here:
<u>brainly.com/question/13040523</u>
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Answer:
1.1ohms
Explanation:
According to ohms law E = IR
If potential difference of a battery is 2.2 V when it is connected across a resistance of 5 ohm and if suddenly the voltage Falls to 1.8V then the current in the 5ohms resistor I = V/R = 1.8/5
I = 0.36A (This will be the load current).
Before we can calculate the value of the internal resistance, we need to know the voltage drop across the internal resistance.
Voltage drop = 2.2V - 1.8V = 0.4V
Then we calculate the internal resistance using ohms law.
According to the law, V = Ir
V= voltage drop
I is the load current
r = internal resistance
0.4 = 0.36r
r = 0.4/0.36
r = 1.1 ohms