All categories

4 years ago

What is role of gravity in our daily life?

1 answer:

4 0

Well for starters, gravity keeps things down on Earth. Also, gravity applies its force on to cars to maintain stability by forcing the tires to make constant contact to the ground creating friction between the rubber and road surface allowing the car to be moved. I'm sure someone else has better ideas!

You might be interested in

Which model of the atom first introduced the idea of a nucleus?

earnstyle [38]

The Rutherford model showed that the atom is mostly empty space with a tiny,massive,positively charged nucleus in the center.

4 0

3 years ago

Read 2 more answers

What is motion me from India pls talk in commets

Fantom [35]

Explanation:

In physics, the motion is the change in position of an object with respect to its surroundings in a given interval of time. The motion of an object with some mass can be described in terms of the following:

distance

displacement

speed

velocity

time

acceleration

5 0

3 years ago

Read 2 more answers

The motion of a piston in an auto engine is simple harmonic. If the piston travels back and forth over a distance of 10 cm and t

chubhunter [2.5K]

Answer:

Maximum force will be 29040 N

Explanation:

We have given mass of the piston m = 1.5 kg

Amplitude A = 10 cm = 0.1 m

Angular speed $\omega =4200rpm=\frac{2\times 3.14\times 4200}{60}=440rad/sec$

We know that angular speed is given by $\omega =\sqrt{\frac{k}{m}}$

$440=\sqrt{\frac{k}{1.5}}$

Squaring both side

$193600=\frac{k}{1.5}$

k = 290400 N/m

Now force is given by $F=kA=290400\times 0.1=29040N$

3 0

3 years ago

An electron traveling with a speed v enters a uniform magnetic field directed perpendicular to its path. The electron travels fo

stepan [7]

Answer:

Explanation:

For circular path in magnetic field

mv² / R = Bqv ,

m is mass , v is velocity , R is radius of circular path , B is magnetic field , q is charge on the particle .

a )

R = mv / Bq

If v is changed to 2v , keeping other factors unchanged , R will be doubled

b )

magnitude of acceleration inside field

= v² / R

= Bqv / m

As v is doubled , acceleration will also be doubled

c )

If T be the time inside the magnetic field

T = π R / v

= π / v x mv / Bq

= π m / Bq

As is does not contain v that means T remains unchanged .

d )

Net force acting on electron

= m v² / R = Bqv

Net force = Bqv

As v becomes twice force too becomes twice .

So a . b , d are correct answer.

4 0

3 years ago

The momentum of an electron is 1.75 times larger than the value computed non-relativistically. What is the speed of the electron

FrozenT [24]

Answer:

Speed of the electron is 2.46 x 10^8 m/s

Explanation:

momentum of the electron before relativistic effect = $M_{0} V$

where $M_{0}$ is the rest mass of the electron

V is the velocity of the electron.

under relativistic effect, the mass increases.

under relativistic effect, the new mass M will be

M = $M_{0}/ \sqrt{1 - \beta ^{2} }$

where

$\beta = V/c$

c is the speed of light = 3 x 10^8 m/s

V is the speed with which the electron travels.

The new momentum will therefore be

==> $M_{0}V/ \sqrt{1 - \beta ^{2} }$

It is stated that the relativistic momentum is 1.75 times the non-relativistic momentum. Equating, we have

1.75 $M_{0} V$ = $M_{0}V/ \sqrt{1 - \beta ^{2} }$

the equation reduces to

1.75 = $1/ \sqrt{1 - \beta ^{2} }$

square both sides of the equation, we have

3.0625 = 1/ $(1 - \beta ^{2} )$

3.0625 - 3.0625 $\beta ^{2}$ = 1

2.0625 = 3.0625 $\beta ^{2}$

$\beta ^{2}$ = 0.67

β = 0.819

substitute for $\beta = V/c$

V/c = 0.819

V = c x 0.819

V = 3 x 10^8 x 0.819 = 2.46 x 10^8 m/s

6 0

4 years ago