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TiliK225 [7]
3 years ago
11

How long does it take for light from a star that is 8 light-years away to reach earth? A. 8 earth minutes B. 16 earth minutes C.

8 earth years D. 16 earth years
Physics
2 answers:
RUDIKE [14]3 years ago
6 0
Your answer would be:

C.) 8 Earth years.

Hope this helps (:!
Hunter-Best [27]3 years ago
4 0
Hey there,

Your question states: <span>How long does it take for light from a star that is 8 light-years away to reach earth?

It take just about (</span>8 earth years) <span> for light from a star that is 8 light-years away to reach earth. That is how </span>FAST it would take.

Hope this helps.
~Jurgen
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A step up transformer has 250 turns on its primary and 500 turns on it secondary. When the primary is connected to a 200 V and t
Zina [86]

Answer:

2000 W

Explanation:

First of all, we need to find the output voltage in the transformer, by using the transformer equation:

\frac{V_1}{N_1}=\frac{V_2}{N_2}

where here we have

V1 = 200 V is the voltage in the primary coil

V2 is the voltage in the secondary coil

N1 = 250 is the number of turns in the primary coil

N2 = 500 is the number of turns in the secondary coil

Solving for V2,

V_2 = N_2 \frac{V_1}{N_1}=(500) \frac{200 V}{250}=400 V

Now we can find the power output, which is given by

P = VI

where

V = 400 V is the output voltage

I = 5 A is the output current

Substituting,

P = (400 V)(5 A) = 2,000 W

3 0
4 years ago
While at a party, you pull up a sound intensity level app on your phone (everyone does stuff like that, right?), and it reads 83
allochka39001 [22]

To solve this problem it is necessary to apply the concepts related to Sound Intensity. The unit most used in the logarithmic scale is the decibel and mathematically this is expressed as

\beta_{dB} = 10log_{10}\frac{I}{I_0}

Where,

\beta_{dB}= Sound intensity level in decibels

I = Acoustic intensity on the linear scale

I_0 = Hearing threshold

According to the values, the total intensity is 32 times the linear intensity and the value in decibels is 83dB

So:

10log_{10}(\frac{32I}{I_0}) = 83

10log(\frac{I}{I_0})+10log(32) = 83

10log(\frac{I}{I_0})= 83-10log(32)

10log(\frac{I}{I_0})= 67.948dB

Therefore the sound intensity due to one person is 67.948dB

8 0
3 years ago
Which of the following is most likely to be attracted to a magnet?
Naya [18.7K]

Answer:

c

Explanation:

because it is made out of metel

7 0
3 years ago
HELP PLS !!!!!!!!!!!!!!!!!!!!]
irina [24]

Answer:

<em>0.25</em>

Explanation:

According to newtons law of motion

\sum F_x = ma

F_f =  ma

nR = ma

nmg = ma

ng = a

n = a/g

g is the acceleration due to gravity

Given

a = 2.42m/s²

g = 9.8m/s²

Substitute into the formula;

n = 2.42/9.8

n = 0.25

<em>Hence the coefficient of kinetic friction is 0.25</em>

<em></em>

6 0
3 years ago
Jack D. Ripper flipped out after missing a Must-Do-It question for the third time on his Minds On Physics assignment. Outraged b
Marrrta [24]

Answer:

Explanation:

Let the velocity after the 4 gram pencil strikes is v .

kinetic energy of the combination = 1/2 m v²

= .5 x ( 4 + 221 ) x 10⁻³ x v² = work done by friction

friction force acting on the combination = 225 x10⁻³x  .325 x 9.8 = .7166 N

work done by friction

= .7166 x .119 = .085 J

.5 x 225 x 10⁻³ v² = .085

v² = .085 / .1125 = .7555

v = .8692 m = 86.92 cm /s

Velocity of combination after collision = 86.92 cm /s

Let velocity of pencil before collision be V

Applying law of conservation of momentum at the time of collision ,

4 x V = 225 x 86.92

V = 4889.25 cm / s

= 48.9 m /s .

5 0
3 years ago
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