Answer:
12.4 m/s²
Explanation:
L = length of the simple pendulum = 53 cm = 0.53 m
n = Number of full swing cycles = 99.0
t = Total time taken = 128 s
T = Time period of the pendulum
g = magnitude of gravitational acceleration on the planet
Time period of the pendulum is given as
![T = \frac{t}{n}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7Bt%7D%7Bn%7D)
![T = \frac{128}{99}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B128%7D%7B99%7D)
T = 1.3 sec
Time period of the pendulum is also given as
![T = 2\pi \sqrt{\frac{L}{g}}](https://tex.z-dn.net/?f=T%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7BL%7D%7Bg%7D%7D)
![1.3 = 2(3.14) \sqrt{\frac{0.53}{g}}](https://tex.z-dn.net/?f=1.3%20%3D%202%283.14%29%20%5Csqrt%7B%5Cfrac%7B0.53%7D%7Bg%7D%7D)
g = 12.4 m/s²
Angry sound level = 70 db
Soothing sound level = 50 db
Frequency, f = 500 Hz
Assuming speed of sound = 345 m/s
Density (assumed) = 1.21 kg/m^3
Reference sound intensity, Io = 1*10^-12 w/m^2
Part (a): Initial sound intensity (angry sound)
10log (I/Io) = Sound level
Therefore,
For Ia = 70 db
Ia/(1*10^-12) = 10^(70/10)
Ia = 10^(70/10)*10^-12 = 1*10^-5 W/m^2
Part (b): Final sound intensity (soothing sound)
Is = 50 db
Therefore,
Is = 10^(50/10)*10^-12 = 18*10^-7 W/m^2
Part (c): Initial sound wave amplitude
Now,
I (W/m^2) = 0.5*A^2*density*velocity*4*π^2*frequency^2
Making A the subject;
A = Sqrt [I/(0.5*density*velocity*4π^2*frequency^2)]
Substituting;
A_initial = Sqrt [(1*10^-5)/(0.5*1.21*345*4π^2*500^2)] = 6.97*10^-8 m = 69.7 nm
Part (d): Final sound wave amplitude
A_final = Sqrt [(1*10^-7)/(0.5*1.21*345*4π^2*500^2)] = 6.97*10^-9 m = 6.97 nm
Crust sitting on top of Milton rock of the mantle
Answer:
2nd bscause there is a reaction