Work shown above! y = 148
Here's the solution,
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now, let's multiply the whole equation with 4
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so,
Case 1. where, 2x - 5 = 0
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case 2. where, 2x - 1 = 0
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The diagonals of a parallelogram bisect each other.
DH = HF and GH = HE
x + 5 = 2y
3x - 1 = 5y + 4
Solve the first equation for x.
x = 2y - 5
Now substitute 2y - 5 for x in the second equation.
3(2y - 5) - 1 = 5y + 4
6y - 15 - 1 = 5y + 4
6y - 16 = 5y + 4
y = 20
Now substitute 20 for y in the first original equation.
x + 5 = 2y
x + 5 = 2(20)
x + 5 = 40
x = 35
Answer: x = 35 and y = 20
