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Mariulka [41]
3 years ago
11

Find the y-intercept for the parabola defined by the equation y=x^2-x-12

Mathematics
1 answer:
o-na [289]3 years ago
6 0

Answer:

The y-intercept is (0,-12).

Step-by-step explanation:

Given equation is y=x^2-x-12.

Now question says to find the y-intercept of the given parabola y=x^2-x-12.

We know that y-intercept means the y-value when x-value equals 0

so let's plug x=0 into given equation y=x^2-x-12  then solve that for y.

y=x^2-x-12

y=0^2-0-12

y=0-0-12

y=-12

Hence the y-intercept is (0,-12).

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Which set of transformations is needed to graph f(x) = –0.1cos(x) – 4 from the parent cosine function?
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One number is 2 less than a second number.twice the second number is 37 more than 5 times the first. Find more the two number
SVEN [57.7K]

Answer:

The numbers are -11 and -9.

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6 0
3 years ago
In the Pythagorean theorem, if a = 5 and b = 12 what does c = ? Show all steps.
Wittaler [7]


your equation is:

a² + b² = c²           

So, plug in what you know.

5² + 12² = c²

5² means 5*5, so your "a" is equal to 25

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to this part, add a and b. you'll get 169.

169 = c²

next, use your calculator and square both sides.

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squaring both sides will get rid of the ² in c, and will give you your new number:

c = 13


5 0
4 years ago
Read 2 more answers
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