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maria [59]
3 years ago
10

In right triangle ABC, A=76º, a=13, and ∠C is the right angle. Solve the triangle.

Mathematics
1 answer:
Gekata [30.6K]3 years ago
8 0

Angles:

A=76 degrees

C=90 degrees

B=180-(90+76)=180-166

=14 degrees

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Question 9
kiruha [24]

The slope of the linear equation is 20 and the y-intercept is 150

<h3>What is a Slope?</h3>

Slope measures how steep a straight line is. It is described as rise over run.

The slope of the linear equation can be found as follows;

He opens the account with $150 and he plans to save $20 each week. Therefore,

let

x = number of weeks

Therefore,

  • y = 20x + 150

where

y = amount in his account after x number of weeks.

Using the slope intercept equation,

<h3>Slope intercept equation:</h3>
  • y =mx + c

where

m = slope

c = y-intercept

Therefore, the slope of the linear equation is 20 and the y-intercept is 150

learn more on slope here: brainly.com/question/8057577

7 0
2 years ago
Find highest common factor 12 &amp; 20
eimsori [14]
It's 4. The factors of 12 are: 1,2,3,4,6,12. The factors of 20 are: 1,2,4,5,10,20.
5 0
3 years ago
Read 2 more answers
Solve the matrix equation. The inverse of the coefficient matrix is given. EXPLAIN. The answer's D. (2/9,-4/3,-1/3)
Lerok [7]

Answer:

Right answer is D number

4 0
3 years ago
The dough that will be used to make a crescent roll is shown below.What is the area of the dough?
vampirchik [111]

Answer:

we need the picture. we cant do this without the picture

Step-by-step explanation:

8 0
3 years ago
A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?
AlekseyPX

Answer:

The width of the sandbox is 42\frac{2}{3} \ ft.

Step-by-step explanation:

Given,

Area of the sandbox = 10\frac{2}{3}=\frac{32}{3}\ ft^2

Length = \frac{1}{4}\ ft

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

Area = Length\times Width

On substituting the given values, we get;

\frac{1}{4}\times w=\frac{32}{3}\\

By cross multiplication method, we get;

w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft

Hence The width of the sandbox is 42\frac{2}{3} \ ft.

5 0
3 years ago
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