The answer is B

This is because to work it out I just used the options by multiplying each one together, for example, for B, I did 2x+3 * x-1 and I got 2x2+x-3 which means it was correct

8 0

3 years ago

A study at a major university concluded that many students are cheating.

marshall27 [118]

The answer is a) 1500 because when you divide 675 (the given number of students that cheated on 1 to 7 courses) by 1500 you get .45 or 45%.

7 0

3 years ago

The mean salary of actuaries is LaTeX: \mu=\$100,000????=$100,000 and the standard deviation is LaTeX: \sigma=\$36,730????=$36,7

krek1111 [17]

Answer:

The lower limit of 95% confidence interval is 99002.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $100,000

Sample mean, $\bar{x}$ = $111,000

Sample size, n = 36

Alpha, α = 0.05

Population standard deviation, σ = $36,730

First, we design the null and the alternate hypothesis

$H_{0}: \mu = \$100,000\\H_A: \mu \neq \$100,000$

We have to find the lower limit of the 95% confidence interval.

95% Confidence interval:

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$111000 \pm 1.96(\dfrac{36730}{\sqrt{36}} )\\\\ = 111000 \pm 11998.4667 \\= (99001.5333,122998.4667)\\ \approx (99002,122999)$

The lower limit of 95% confidence interval is 99002.

6 0

4 years ago