20.5 is the answer, have a great day!
Answer:
m is -12/7 and b is -64/7
Step-by-step explanation:
Use rise over run (change in y / change in x) to find the slope, m:
(-4 - 8) / (-3 + 10)
= -12/7
So, m is -12/7.
Plug in this value and a point into y = mx + b, then solve for b:
y = mx + b
-4 = -12/7(-3) + b
-4 = 36/7 + b
-64/7 = b
So, m is -12/7 and b is -64/7
Answer:
c. <N
Step-by-step explanation:
please mark me as a brainlest!
Answer:
a) 32
b) 67.613
Step-by-step explanation:
<em><u> In Game 3, Emerson struck out 42 times in 140 times at-bat.</u></em>
<em><u>Part A</u></em>
<em><u>Drag numbers to complete the proportion to represent the percent of strikeouts per at-bats.</u></em>
<em><u>Numbers may be used once or not at all.</u></em>
<em><u /></em>
<em><u>Part B</u></em>
<em><u>What percentage of times at bat did Emerson actually hit the ball?</u></em>
Part A
Total number of strikeouts= 30+40+42= 112
Total number of at bats = 90+120+140= 350
strikeouts : times
112: 350
p:100
Using cross product rule
p/100= 112/350
p * 350= 112*100
or p= 11200/350= 32
It means that there were 32 strikeouts if 100 times were bat at hits.
Part B:
Total number of strikeouts= 30+40+42= 112
Total number of at bats = 90+120+140= 350
But we need the percentage of times at bat hit
Therefore
Hits= times - strikeouts= 350-112= 238
Percentage = 238/352*100= 67.613
Check
The above answers are correct because
100-32 = 68
68 ≅ 67.613
