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seraphim [82]
3 years ago
10

How do you solve b to find the set p

Mathematics
1 answer:
Ilya [14]3 years ago
8 0

\tan p=1\iff p=45^o+180^ok,\ k\in\mathbb{Z}

We have: 0^o\leq p\leq540^o

Therefore

P=\{45^o,\ 225^o,\ 405^o\}

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What's the converse of the statement "if it is snowing, then it is my birthday"
Drupady [299]

The converse would be "If it is my birthday, then it is snowing."

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3 years ago
What's the distance between (-14,-18) and (-25,-23)
Serjik [45]

Answer:

the answer is 12.08

Step-by-step explanation:

Use the distance between point formula

3 0
4 years ago
X+2y + z = 4<br> 1. 4y - 3z = 1<br> y + 5z = 6
Feliz [49]

Answer:

The values of x = y = z = 1  

Step-by-step explanation:

Given three linear equation as ,

x + 2y + z = 4               .......a

     4y - 3z = 1               .......b

       y + 5z = 6             ........c

Now solve eq a and b first

   4y - 3z = 1   ×  5

    y + 5z = 6  ×  3

Or, 20y - 15z = 5

      3 y + 15z = 18

so ,(20y - 15) + (3y +15 ) = 5 +18

or,   23 y = 23  

∴           y = 1

Now put this y value in eq c

so , 1 + 5z = 6 ,

Or,       5z = 6-1 =5

∴            z = 1

Again put this y and z value in eq a

so, x + 2(1) + (1) = 4

Or,                x   = 4 -3

∴                   x = 1

Hence from the above solutions , the value of x = y =z = 1        Answer

4 0
3 years ago
Prove that:<br><br>1+cot²a / 1 + cosec a = cosec a<br> ​
fgiga [73]

Step-by-step explanation:

LHS= 1 + cot^2A/1+cosecA

=(1+cosecA + cot^2A)/1+cosecA

{By using basic trigonometric theorem cot^2A = cosec^2A - 1}

=(1+cosecA + cosec^2A - 1)/(1+cosecA)

=(cosecA + cosec^2A)/(1+cosecA)

=[cosecA (1+cosecA)]/(1+cosecA)

{Cancelling 1+cosecA}

=cosecA

3 0
3 years ago
In a class of 42 students the number of boys is 2/5 of the girls . find the number of boys and girls
Ksju [112]
In plain and short, we simply divide 42 by (2+5) and distribute accordingly.

\bf \cfrac{boys}{girls}\qquad 2:5\qquad \cfrac{2\cdot \frac{42}{2+5}}{5\cdot \frac{42}{2+5}}\implies \cfrac{2\cdot 6}{5\cdot 6}\implies \cfrac{12}{30}
3 0
3 years ago
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