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Romashka [77]
3 years ago
13

What's the converse of the statement "if it is snowing, then it is my birthday"

Mathematics
1 answer:
Drupady [299]3 years ago
5 0

The converse would be "If it is my birthday, then it is snowing."

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HELP FAST 20 POINTS PLEASE HELP IM BEGGINGGg
Kobotan [32]

Answer:

3.5C = 1n

Step-by-step explanation:

For every $3.5 is 1 mile.

I do not know what other currency this could be, as I only live in the US. Therefor, i'm assuming it's US Dollars. But this does not effect the question, so moving on.

Brainliest for being like only a fortnight late...?

3 0
3 years ago
The average homicide rate for the cities and towns in a state is 10 per 100,000 population with a standard deviation of 2. If th
zlopas [31]

Answer:

P(X>8)=P(\frac{X-\mu}{\sigma}>\frac{8-\mu}{\sigma})=P(Z>\frac{8-10}{2})=P(Z>-1)  

And we can find this probability with the complement rule:  

P(Z>-1)=1-P(Z  

Step-by-step explanation:

Previous concepts  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem  

Let X the random variable that represent the average homicide rate for the cities of a population, and for this case we know the distribution for X is given by:  

X \sim N(10,2)  

Where \mu=10 and \sigma=2  

We are interested on this probability  

P(X>8)  

And the best way to solve this problem is using the normal standard distribution and the z score given by:  

z=\frac{x-\mu}{\sigma}  

If we apply this formula to our probability we got this:  

P(X>8)=P(\frac{X-\mu}{\sigma}>\frac{8-\mu}{\sigma})=P(Z>\frac{8-10}{2})=P(Z>-1)  

And we can find this probability with the complement rule:  

P(Z>-1)=1-P(Z  

5 0
3 years ago
Assume that the paired data came from a population that is normally distributed. using a 0.05 significance level and dequalsxmin
Artemon [7]
"<span>Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d = (x - y), find \bar{d}, s_{d}, the t-test statistic, and the critical values to test the claim that \mu_{d} = 0"

You did not attach the data, therefore I can give you the general explanation on how to find the values required and an example of a random paired data.

For the example, please refer to the attached picture.

A) Find </span><span>\bar{d}
You are asked to find the mean difference between the two variables, which is given by the formula:
\bar{d} =  \frac{\sum (x - y)}{n}

These are the steps to follow:
1) compute for each pair the difference d = (x - y)
2) sum all the differences
3) divide the sum by the number of pairs (n)

In our example: 
</span><span>\bar{d} =  \frac{6}{8} = 0.75</span>

B) Find <span>s_{d}
</span><span>You are asked to find the standard deviation, which is given by the formula:
</span>s_{d} =  \sqrt{ \frac{\sum(d - \bar{d}) }{n-1} }

These are the steps to follow:
1) Subtract the mean difference from each pair's difference 
2) square the differences found
3) sum the squares
4) divide by the degree of freedom DF = n - 1

In our example:
s_{d} = \sqrt{ \frac{101.5}{8-1} }
= √14.5
= 3.81

C) Find the t-test statistic.
You are asked to calculate the t-value for your statistics, which is given by the formula:
t =  \frac{(\bar{x} - \bar{y}) - \mu_{d} }{SE}

where SE = standard error is given by the formula:
SE =  \frac{ s_{d} }{ \sqrt{n} }

These are the steps to follow:
1) calculate the standard error (divide the standard deviation by the number of pairs)
2) calculate the mean value of x (sum all the values of x and then divide by the number of pairs)
3) calculate the mean value of y (sum all the values of y and then divide by the number of pairs)
4) subtract the mean y value from the mean x value
5) from this difference, subtract  \mu_{d}
6) divide by the standard error

In our example:
SE = 3.81 / √8
      = 1.346

The problem gives us <span>\mu_{d} = 0, therefore:
t = [(9.75 - 9) - 0] / 1.346</span>
  = 0.56

D) Find t_{\alpha / 2}
You are asked to find what is the t-value for a 0.05 significance level.

In order to do so, you need to look at a t-table distribution for DF = 7 and A = 0.05 (see second picture attached).

We find <span>t_{\alpha / 2} = 1.895</span>

Since our t-value is less than <span>t_{\alpha / 2}</span> we can reject our null hypothesis!!

7 0
3 years ago
The diameter of a circle is 20m. Find the circumference to the nearest tenth
AlladinOne [14]

Answer:

62.8

Step-by-step explanation:

Using the circumference formula (πd) we can see that the answer is 20π, or 62.8

3 0
2 years ago
How do you solve for X in a fraction
Andrews [41]

By cross-multiplying, we get

15x + 30 = 24

15x = -6

x = -3 / 5



7 0
3 years ago
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