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vaieri [72.5K]
3 years ago
15

What is (2/9v - ( -1/3v + 5/9)

Mathematics
1 answer:
Airida [17]3 years ago
7 0
-v/9-5/9 I really don't know if it's fully correct, but I hope it is!
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Help me out please and thank you
Rashid [163]

Answer:

I got B

75+20+85=180

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3 years ago
Lan has $6,000. He wants to buy a car within $1,500 of this
Elena L [17]

Answer:blm

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
I subtract 3 from a certain number, multiply the result by 5 and then add 9 if the final result is 54. find the original number
Sergeu [11.5K]

(x-3)\cdot 5+9=54\\5x-15=45\\5x=60\\x=12

8 0
2 years ago
Circle C with center at (−4, 6) and radius 2 is similar to circle D with center at (6, −2) and radius 4. Below is an incorrect i
BlackZzzverrR [31]

We are told that circle C has center (-4, 6) and a radius of 2.

We are told that circle D has center (6, -2) and a radius of 4.


If we move circle C's center ten units to the right and eight units down, the new center would be at (-4 + 10), (6 - 8) = (6, -2). So step 1 in the informal proof checks out - the centers are the same (which is the definition of concentric) and the shifts are right.

Let's look at our circles. Circle C has a radius of 2 and is inside circle D, whose radius is 4. Between Circle C and Circle D, the radii have a 1:2 ratio, as seen below:

\frac{1}{2} = \frac{radius--circle C}{radius--circle D}

If we dilate circle C by a factor of 2, it means we are expanding it and doubling it. Our circle has that 1:2 ratio, and doubling both sides gives us 2:4. The second step checks out.

Translated objects (or those that you shift) can be congruent, and dilated objects are used with similarity (where you stretch and squeeze). The third step checks out.


Thus, the argument is correct and the last choice is best.

3 0
4 years ago
Pls pls pls help if ur good with angles and sides ​
liq [111]

Answer:

∆PQR: Equilateral Triangle

∆PRT: Scalene Triangle

∆TQS: Isosceles Triangle

∆QNP: Right Triangle

Step-by-step explanation:

∆PQR is an Equilateral Triangle because all of its angles are equal (60°).

∆PRT is a Scalene Triangle because none of its sides are equal.

The triangle above it is equilateral, and one side length is 14, meaning all of its side lengths are 14.

This makes the top of ∆PRT 14. The hypotenuse is given and it’s 18.

The last side left is clearly shorter than both, meaning none of the sides are equal.

∆TQS is an Isosceles Triangle because 2 angles are equal.

The base angles are both 76°.

∆QNP is a Right Triangle because segment QN and PR are perpendicular, creating two 90° angles on both sides.

For number 10, I suggest using a graphing calculator or desmos to graph the points. (Or you can just add the points but I suggest graphing).

From there, you can count the length of each side.

Segment DE: 9

Segment EF: 8

Segment FD: 10

This makes ∆DEF in number 10 a Scalene Triangle because none of its sides are equal.

For number 11, I also suggest graphing the points and counting the sides.

Segment DE: 7

Segment EF: 9

Segment FD: 7

This makes ∆DEF in number 11 an Isosceles Triangle because 2 of its sides are equal.

Hope this helps! :)

4 0
3 years ago
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