State the horizontal asymptote of the rational function. For full credit, explain the reasoning you used to find the horizontal
1 answer:
So here are the rules of horizontal asymptotes:
- Degree of Numerator > Degree of Denominator: No horizontal asymptote
- Degree of Numerator = Degree of Denominator:
- Degree of Numerator < Degree of Denominator: y = 0
Looking at the rational function, since the degree of the numerator is 2 and the degree of the denominator is 1 (and 2 > 1), this means that <u>this function has no horizontal asymptote.</u>
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Answer:
498 m
Step-by-step explanation:
The AAA theorem states that triangles are similar if all three corresponding angles are equal.
1. Compare triangles FHS and ILS
(a) Reason for similarity
∠F = ∠I = 90°
∠S is common.
∴ ∠H = ∠L
(b) Calculate SL
2. Compare triangles ILS and GLE
(a) Reason for similarity
∠I = ∠G = 90°
∠L is common.
∴ ∠S = ∠E
(b) Calculate LE
3. Calculate EH
LE + EH + HS = LS
304.0 m + EH + 380 m = 1182 m
EH + 684 m = 1182 m
EH = 498 m
The distance from E to H is 498 m.
Answer:
The saving of all three person are
The Pedro's saving is $ 30
The Michael's saving is $ 10
The Kevin's saving is $ 90
Step-by-step explanation:
Given as :
The three person namely Michael , Pedro , Kevin
The total saving of all together = $ 130
Let The Michael's saving = $ M
The Pedro's saving = $ P
The Kevin's saving = $ k
I.e Michael's saving + Pedro's saving + Kevin's saving = $ 130
Or, M + P + K = $ 130
again ,
Kevin saved 3 times more than Pedro
I.e K = 3 × P
And , Michael save $ 20 less than Pedro
I.e M = P - $ 20
Now
∵ M + P + K = $ 130
or, ( P - $ 20) + P + 3 × P = $ 130
Or, 5 P - $ 20 = $ 130
Or, 5 P = $ 130 + $ 20
Or, 5 P = $ 150
∴ P = $
I.e P = $ 30
So The Pedro's saving = P = $ 30
And
M = P - $ 20
∴, M = $ 30 - $ 20
I.e M = $ 10
So, The Michael's saving = M = $ 10
Similarly
K = 3 × P
∴ k = 3 × $ 30
I.e K = $ 90
So, The Kevin's saving = k = $ 90
Hence The saving of all three person are
The Pedro's saving is $ 30
The Michael's saving is $ 10
The Kevin's saving is $ 90
Answer
Answer:
E. 0.11
Step-by-step explanation:
We have these following probabilities:
A 10% probability that a person has the flu.
A 90% probability that a person does not have the flu, just a cold.
If a person has the flu, a 99% probability of having a runny nose.
If a person just has a cold, a 90% probability of having a runny nose.
This can be formulated as the following problem:
What is the probability of B happening, knowing that A has happened.
It can be calculated by the following formula
Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.
In this problem, we have that:
What is the probability that a person has the flu, given that she has a runny nose?
P(B) is the probability that a person has the flu. So P(B) = 0.1.
P(A/B) is the probability that a person has a runny nose, given that she has the flu. So P(A/B) = 0.99.
P(A) is the probability that a person has a runny nose. It is 0.99 of 0.1 and 0.90 of 0.90. So
What is the probability that this person has the flu?
The correct answer is:
E. 0.11