If a 12 oz bottle of shampoo lasted for 16 weeks, we have a ratio of 12:16 which can be shortened to 3:4.
Now if we have 18 oz bottle we know that it's 1/2 more than 12 oz bottle, so the ratio will be also 1/2 more. So if it was 12:16, the new ratio will be:
12 + (1/2 * 12) : 16 + (1/2 * 16)
12 + 6 : 16 + 8
18 : 24
It means that 18 oz bottle should last for 24 weeks. Of course the ratio has to stay the same in its lowest form in both situations and as 18:24 can be shortened to 3:4, it proves it's correct :)
Answer:
50° and 130°
Step-by-step explanation:
∠1 is a chord- chord angles and is calculated as
∠1 = 0.5( arc RQ + arc ST) = 0.5(53 + 47)° = 50°
∠1 and ∠2 form a straight angle and are supplementary, hence
∠2 = 180° - 50° = 130°
Answer:
y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1
Step-by-step explanation:
y" + y' + y = 1
This is a second order nonhomogenous differential equation with constant coefficients.
First, find the roots of the complementary solution.
y" + y' + y = 0
r² + r + 1 = 0
r = [ -1 ± √(1² − 4(1)(1)) ] / 2(1)
r = [ -1 ± √(1 − 4) ] / 2
r = -1/2 ± i√3/2
These roots are complex, so the complementary solution is:
y = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t)
Next, assume the particular solution has the form of the right hand side of the differential equation. In this case, a constant.
y = c
Plug this into the differential equation and use undetermined coefficients to solve:
y" + y' + y = 1
0 + 0 + c = 1
c = 1
So the total solution is:
y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1
To solve for c₁ and c₂, you need to be given initial conditions.
Answer:
-25/52
Step-by-step explanation:
that's what I got.
