56:12

Mathematics

1 answer:

Gre4nikov [31]2 years ago

5 0

Answer:

The official answer is {C} ive previously taken the test

Step-by-step explanation:

I have taken the test before hand.

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The perimeter of the triangle is 30 cm.

Paraphin [41]

Answer:

Step-by-step explanation:

3a=30... equation 1

2a+2b=30... equation2

equation 2 => a+b=15 ... equation 3

equation 1 => a = 10 ... equation 4

equation 4 & equation 3 => b = 5

5^2 = 25

4 0

3 years ago

Read 2 more answers

5. Alex bought two hots dogs, fries, and a water at the food truck. The hot dogs were

Citrus2011 [14]

Answer:

2.60

Step-by-step explanation:

4.70 hotdogs

fries 1.25

water 2.60= 8.55-10=1.45

4 0

3 years ago

Hi, help with question 18 please. thanks

Vadim26 [7]

Answer:

See Below.

Step-by-step explanation:

We are given the equation:

$\displaystyle y^2 = 1 + \sin x$

And we want to prove that:

$\displaystyle 2y\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right) ^2 + y^2 = 1$

Find the first derivative by taking the derivative of both sides with respect to x:

$\displaystyle 2y \frac{dy}{dx} = \cos x$

Divide both sides by 2y:

<h3> $\displaystyle \frac{dy}{dx} = \frac{\cos x}{2y}$ </h3>

Find the second derivative using the quotient rule:

$\displaystyle \begin{aligned} \frac{d^2y}{dx^2} &= \frac{(\cos x)'(2y) - (\cos x)(2y)'}{(2y)^2}\\ \\ &= \frac{-2y\sin x-2\cos x \dfrac{dy}{dx}}{4y^2} \\ \\ &= -\frac{y\sin x + \cos x\left(\dfrac{\cos x}{2y}\right)}{2y^2} \\ \\ &= -\frac{2y^2\sin x+\cos ^2 x}{4y^3}\end{aligned}$