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zysi [14]
3 years ago
13

Consider the following least squares specification between test scores and the student - teacher ratio: TestScore = 557.8 + 36.4

2 In (Income). According to this equation, a 1% increase income is associated with an increase in test scores of :A. 36.42 points B. cannot be determined from the information given here C. 0.36 points D. 557.8 points
Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0

Answer:

Test score_i= 557.8 +36.42 Income

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

Test score_f = 557.8  + (36.42* 1.01 Income)= 557.8 +36.7842 Income

And the net increase can be founded like this:

Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642

So then the net increase would be:

C. 0.36 points

Step-by-step explanation:

For this case we have the following linear relationship obtained from least squares between test scores and the student-teacher ratio:

Test score_i= 557.8 +36.42 Income

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

Test score_f = 557.8  + (36.42* 1.01 Income)= 557.8 +36.7842 Income

And the net increase can be founded like this:

Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642

So then the net increase would be:

C. 0.36 points

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Solve the following equation for 0°≤x≤360° : 2 cot 2x + 3 = 0
evablogger [386]

Answer:

π

2

,

3

⋅

π

2

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⋅

π

4

,

7

⋅

π

4

Explanation:

Factorizing your equation we get

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x

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0

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(

x

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=

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we get the following Solutions in the given interval

x

=

π

72

or

x

=

3

π

2

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cot

(

x

)

=

−

1

so

cos

(

x

)

=

−

sin

(

x

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and we get

x

=

3

π

4

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x

=

7

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