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zysi [14]
3 years ago
13

Consider the following least squares specification between test scores and the student - teacher ratio: TestScore = 557.8 + 36.4

2 In (Income). According to this equation, a 1% increase income is associated with an increase in test scores of :A. 36.42 points B. cannot be determined from the information given here C. 0.36 points D. 557.8 points
Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0

Answer:

Test score_i= 557.8 +36.42 Income

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

Test score_f = 557.8  + (36.42* 1.01 Income)= 557.8 +36.7842 Income

And the net increase can be founded like this:

Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642

So then the net increase would be:

C. 0.36 points

Step-by-step explanation:

For this case we have the following linear relationship obtained from least squares between test scores and the student-teacher ratio:

Test score_i= 557.8 +36.42 Income

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

Test score_f = 557.8  + (36.42* 1.01 Income)= 557.8 +36.7842 Income

And the net increase can be founded like this:

Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642

So then the net increase would be:

C. 0.36 points

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Answer:

Her centripetal acceleration during the turn at each end of the track is 0.432\, \frac{m}{s^{2}}

Step-by-step explanation:

Total distance covered in one round , D= 400 m

Time taken to cover one round , T = 1 min 40 s = 100 sec

Speed of runner , V=\frac{D}{T}=\frac{400}{100}\, \frac{m}{s}= 4.0\, \frac{m}{s}

Now centripetal acceleration is given by

a_c=\frac{V^{2}}{R}

where V= 4.0\frac{m}{s}

Radius, R= \frac{Diameter}{2}=\frac{74}{2}m=37\, m

\therefore a_c=\frac{4^{2}}{37}\, \frac{m}{s^{2}}=0.432\, \frac{m}{s^{2}}

Thus her centripetal acceleration during the turn at each end of the track is 0.432\, \frac{m}{s^{2}}

4 0
3 years ago
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Elina [12.6K]
110+90+145=345
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Answer:

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Step-by-step explanation:

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1 year ago
-12 + 8a = -a + 6(2a - 2)
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Answer:

41/6

Step-by-step explanation:

-12+81=-1+6(2a-2)

first distribute:

-12+81=-1+12a-12

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<u>-12+81</u>= <u>-1</u>+12a<u>-12</u>

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2 years ago
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Please please help me in these questions ​
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a. a=40° (alternate interior angles)

b+40°=180°( supplementary angles)

b=140°

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d=b=140°( corresponding angles)

b. 2a+120°=180° (supplementary angles)

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