18 inches.
12/4=3 so you would multiply 6•3 to get 18
x^2 - 7x + 15
_________________
(x+4)/ x^3 - 3x^2 - 13x + 78
- x^3 + 4x^2
----------------
- 7x^2 - 13x
- - 7x^2 - 28x
------------------
15x + 78
- 15x + 60
-------------
18
remainder = 18
Answer:
The length of the edge of the cube = 4 inches
Step-by-step explanation:
* Lets describe the cube
- It has 6 faces all of them are squares
- It has 8 vertices
- It has 12 equal edges
∵ The volume of any formal solid = area of the base × height
∵ The base of the cube is a square
∴ Area base = L × L = L² ⇒ L is the length of the edge of it
∵ All edges are equal in length
∴ Its height = L
∴ The volume of the cube = L² × L = L³
* Now we have the volume and we want to find the
length of the edges
∵ Its volume = 64 inches³
∴ 64 = L³
* Take cube root to the both sides
∴ ∛64 = ∛(L³)
∴ L = 4 inches
* The length of the edge of the cube = 4 inches
Answer:
952 cubic feet
Step-by-step explanation:
The diameter is 21, so the radius is 10.5. The area of a circle is πr^2, so 10.5^2π, or 110.25π. The pool is filled 9 inches from the top, so it is 3.5 feet - 9 inches high, 9 inches is 0.75 feet, so 2.75 feet filled. Now multiply 110.25π by 2.75 to get 303.1875π and then 952.4916, closer to 952 cubic feet.
Tell me if I'm right
Left to right. Whatever comes first (multiplication or division) you do. This is all part of the PEMDAS/Order of operations.
Hopefully I solved your problem! :)
