Question

A puck sliding on ice approaches a 20 degrees ramp at 10 m/s with coefficient of friction 0.2. How high will it go up the ramp along the ramp’s surface?

Answer 1

Answer:

it will go up along the inclined plane by d = 9.62 m

Explanation:

As we know that puck is moving upward along the slide

then the net force opposite to its speed is given as

$F_{net} = - mgsin\theta - \mu mgcos\theta$

so here deceleration is given as

$a = -g(sin\theta + \mu cos\theta)$

now plug in all values in it

$a = -9.81(sin20 + 0.2cos20)$

$a = -5.2 m/s^2$

now the distance covered by the puck along the plane is given as

$v_f^2 - v_i^2 = 2 a d$

$0 - 10^2 = 2(-5.2)d$

$d = 9.62 m$