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user100 [1]
4 years ago
11

Why are peer reviews important

Physics
2 answers:
Gre4nikov [31]4 years ago
7 0

Answer: So they can find your mistakes that you made you skipped over

Explanation:

larisa [96]4 years ago
3 0

Answer: You can get help from you peers, they can help you improve your answers

You might be interested in
A grasshopper floating in water generates waves at a rate of three per second with a wavelength of two centimeters. (a) What is
Nastasia [14]

Answer:

(a) 0.33 second

(b) 6 cm/s

Explanation:

Frequency, f = 3 waves per second

wavelength, λ = 2 cm = 0.02 m

(a) The period of wave is defined as the time taken by the wave to complete one oscillation. It is the reciprocal of frequency.

T = 1 / f = 1 / 3 = 0.33 second

(b) the relation between wave velocity, frequency and wavelength is given by

v = f x λ

v = 3 x 0.02 = 0.06 m /s

v = 6 cm /s

8 0
3 years ago
A photon of light has a wavelength of about 600 nm (1nm = 1 x 10-9 m). What is the energy of this photon of light? Show all calc
bezimeni [28]
Wavelength = 600 nm = 600 × 10^(-9)
speed of light = c = 3 × 10^8
planck constant = h = 6.63 × 10^(-34)

energy of photon = hc/wavelength
 = 6.63 × 10^(-34) × 3 × 10^8/600 × 10^(-9)
 = 1.9 × 10^(-25)/6 × 10^(-7)
 = 0.31 × 10^(-16)
 = 3.1 × 10^(-17)
6 0
3 years ago
Two objects (38.0 and 17.0 kg) are connected by a massless string that passes over a massless, frictionless pulley. The pulley h
fgiga [73]

Answer:

a) 3.7 m/s^2

b) 231.8 N

Explanation:

Let m1 be mass of the first object (m1 = 38.0 kg) and let m2 be the mass of the second object (m2 = 17.0 kg ). Let a be the acceleration of the two objects. Let F1 be the force of gravity exerted on m1 and F2 be the force of gravity exerted on m2. Let M = m1 +m2

a)

F1 = m1g and F2 = m2g

So Fnet = F1 + F2

Since the pulleys will move in different directions when accelerating...

Fnet = F1 - F2

M×a = m1g - mg2

M×a = g×(m1 -m2)

a = g×(m1 - m2)/M

a = 9.8×(38 - 17)/(38 + 17)

a = 3.7 m/s^2

b)

Looking at the part for m2

Fnet  = T - m2g

-m2×a = T - m2g

T = m2(g - a)

T = 231.8 N

7 0
3 years ago
A force of 100 N is applied to a crate at an angle of 60° to the horizontal surface.
ad-work [718]

Answer:

100 J

Explanation:

Given:

Force acting on the crate is, F=100\ N

Displacement of the crate is, S=2\ m

Angle between the direction of force and displacement is, \theta=60\°

Now, work done by a force 'F' causing a displacement 'S' such that the angle between the force and displacement is \theta is given as:

Work=F\times S\times \cos\theta

Now, plug in 100 N for 'F', 2 m for 'S', and 60° for \theta. This gives,

Work=(100\ N)(2\ m)(\cos(60))\\\\Work=(200\times 0.5)\ \textrm{N-m}\\\\Work=100\ J

Therefore, the work done by the force is 100 J.

8 0
4 years ago
Describe how you could conduct an experiment to quantify photosynthesis under different conditions, such as different amounts of
Mama L [17]

different amounts of sunlight can be conducted throughout the world but some special are

Explanation:

take bisc(*- calcoihvx to ordz which makes to easy

6 0
3 years ago
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