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2 years ago

Which type of reaction does this diagram represent?

Physics

2 answers:

DerKrebs [107]2 years ago

6 0

Answer:

A. a chain reaction that is caused by nuclear fission

Explanation:

I just took test

Ugo [173]2 years ago

4 0

The diagram represents a chain reaction that is caused by nuclear fission.

<h3>What is a nuclear fission reaction?</h3>

A nuclear fission reaction is a reaction in which the nucleus of a larger atom is split into two or more smaller nucleus of atoms.

Nuclear fission can proceed in the form of a chain reaction in which the products of the first fission reaction are used to initiate further fission reactions.

Therefore, the diagram represents a chain reaction that is caused by nuclear fission.

Learn more about nuclear fission at: brainly.com/question/22155336

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Jon and Jim push a dead car forward to the gas station. Jon pushes with 90N while Jim pushes 80 N.

Nina [5.8K]

The resultant of the two forces is about 170 N.

<h3>What is the resultant force?</h3>

The term resultant force has to do with the single force that has the same magnitude and direction as two or more forces acting together.

In this case, the both forces are acting in the forward direction. This implies that the resultant force is 90 N + 80 N = 170 N.

Learn more about resultant force:brainly.com/question/16380983

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5 0

2 years ago

Can y’all please help me with this 3 part question?

klio [65]

Answer:

Vf = 210 [m/s]

Av = 105 [m/s]

y = 2205 [m]

Explanation:

To solve this problem we must use the following formula of kinematics.

$v_{f} =v_{o} +g*t$

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0 (released from the rest)

g = gravity acceleration = 10 [m/s²]

t = time = 21 [s]

Vf = 0 + (10*21)

Vf = 210 [m/s]

Note: The positive sign for the gravity acceleration means that the object is falling in the same direction of the gravity acceleration (downwards)

The average speed is defined as the sum of the final speed plus the initial speed divided by two. (the initial velocity is zero)

Av = (210 + 0)/2

Av = 105 [m/s]

To calculate the distance we must use the following equation of kinematics

$v_{f} ^{2} =v_{o} ^{2} +2*g*y\\\\(210)^{2} = 0 + (2*10*y)$

44100 = 20*y

y = 2205 [m]

5 0

3 years ago

If the normal force exerted by the track on the car when it is at the top of the track (point B) is 6.00 N , what is the normal

Eddi Din [679]

Answer:

So, the force, F is the agent which provides the basic property of motion or rest to the body.While, the car is more obviously to have a mass, m and that the angle withe road or surface is also given which is normal to the road(i.e angle =90 degree). Then we say that lets say that the car is moving with the constant velocity of 20 m/sec and its kept unchanged by the car. So, we have the mass, m as 1 kg for the car and the value of the gravity we have the g=9.8 m/sec.

Now,

We have F=ma,

and a=v/t,

so we can have another equation for it as,

Now, providing the required data to, it; ∴t =2 sec,

F=(1)×(20/2),