A 5.20 mol 5.20 mol sample of solid A A was placed in a sealed 1.00 L container and allowed to decompose into gaseous B B and C
. C. The concentration of B B steadily increased until it reached 1.10 M, 1.10 M, where it remained constant. A ( s ) − ⇀ ↽ − B ( g ) + C ( g ) A(s)↽−−⇀B(g)+C(g) Then, the container volume was doubled and equilibrium was re‑established. How many moles of A A remain?
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Mass = 0.201kg
Energy = 15J
temperature change = 10C
Energy(E) = mass(m) × specific heat capacity(c) × temperature change(θ)
we can rearrange this to make specific heat capacity the subject
c =
c =
c =7.46268657
Energy = 15J
temperature change = 10C
Energy(E) = mass(m) × specific heat capacity(c) × temperature change(θ)
we can rearrange this to make specific heat capacity the subject
c =
c =
c =7.46268657