A 5.20 mol 5.20 mol sample of solid A A was placed in a sealed 1.00 L container and allowed to decompose into gaseous B B and C
. C. The concentration of B B steadily increased until it reached 1.10 M, 1.10 M, where it remained constant. A ( s ) − ⇀ ↽ − B ( g ) + C ( g ) A(s)↽−−⇀B(g)+C(g) Then, the container volume was doubled and equilibrium was re‑established. How many moles of A A remain?
1 answer:
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The velocity of tennis racket after collision is 14.96m/s
<u>Explanation:</u>
Given-
Mass, m = 0.311kg
u1 = 30.3m/s
m2 = 0.057kg
u2 = 19.2m/s
Since m2 is moving in opposite direction, u2 = -19.2m/s
Velocity of m1 after collision = ?
Let the velocity of m1 after collision be v
After collision the momentum is conserved.
Therefore,
m1u1 - m2u2 = m1v1 + m2v2
Therefore, the velocity of tennis racket after collision is 14.96m/s
Answer:
Fundamental frequency in the string will be 25 Hz
Explanation:
We have given length of the string L = 1.2 m
Speed of the wave on the string v = 60 m/sec
We have to find the fundamental frequency
Fundamental frequency in the string is equal to , here v is velocity on the string and L is the length of the string
So frequency will be equal to
So fundamental frequency will be 25 Hz