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klio [65]
4 years ago
12

A 5.20 mol 5.20 mol sample of solid A A was placed in a sealed 1.00 L container and allowed to decompose into gaseous B B and C

. C. The concentration of B B steadily increased until it reached 1.10 M, 1.10 M, where it remained constant. A ( s ) − ⇀ ↽ − B ( g ) + C ( g ) A(s)↽−−⇀B(g)+C(g) Then, the container volume was doubled and equilibrium was re‑established. How many moles of A A remain?

Physics
1 answer:
Furkat [3]4 years ago
4 0

Answer: 3.5 moles

Explanation: see attachment

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Consider two transformers. Transformer A has 300 turns on its primary and 500 turns on its secondary. Transformer B has 250 turn
rusak2 [61]

Answer:

Secondary voltage on second transformer is 200 volt.

Explanation:

It is given two transformer

Let us consider first transformer.

Number of turns in primary N_p=300

Numb er of turns in secondary N_s=500

Now consider second transformer

Number of turns in primary N_p=250

Number of turns in secondary N_s=1000

Now it is given that same voltage of 50 volt is applied to primary of both the transformer.

For second transformer

\frac{N_p}{N_s}=\frac{V_p}{V_s}

\frac{250}{1000}=\frac{50}{V_s}

V_s=200volt

So secondary voltage on second transformer is 200 volt

4 0
4 years ago
Unpolarized light passes through a vertical polarizing filter, emerging with an intensity I0. The light then passes through a ho
antiseptic1488 [7]

To solve this problem it is necessary to apply the concepts related to Malus' law. Malus' law indicates that the intensity of a linearly polarized ray of light that passes through a perfect analyzer with a vertical optical axis is equivalent to:

I = I_0 cos^2(\theta)

I_0 = Indicates the intensity of the light before passing through the Polarizer,

I = The resulting intensity, and

\theta = Indicates the angle between the axis of the analyzer and the polarization axis of the incident light.

There is 3 polarizer, then

For the exit of the first polarizer we have that the intensity is,

I_2 = I_0cos^2(45)

For the third polarizer then we have,

I_3 = I_2 cos^{2}(45)

Replacing with the first equation,

I_3 =  I_0cos^2(45)cos^{2}(45)

I_3 = I_0 (\frac{1}{2})(\frac{1}{2})

I_3 = I_0 \frac{1}{4}

Therefore the transmitted intensity now is \frac{1}{4} of the initial intensity.

5 0
4 years ago
The gravitational force between a satellite and Earth’s moon is 324 N. The mass of the moon is 7.3 × 1022 kg.
tiny-mole [99]

450 kg is your answer middle school physic


8 0
3 years ago
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What does the horizontal line through the center of the wave on a graph represent?
aleksandrvk [35]

Answer:

This is the midline or the medium which is the exact middle of the graphs minimum and maximum points(which are the amplitude)

8 0
3 years ago
Which of these is true for the two poles of a magnet?
mina [271]
The correct answer to this problem would be that like poles repel and unlike poles attract.

N and N poles repel
S and S poles repel
N and S poles attract
S and N poles attract

Answer: D) like poles repel each other. unlike poles attract each other

I hope this helps!
3 0
3 years ago
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