A 5.20 mol 5.20 mol sample of solid A A was placed in a sealed 1.00 L container and allowed to decompose into gaseous B B and C
. C. The concentration of B B steadily increased until it reached 1.10 M, 1.10 M, where it remained constant. A ( s ) − ⇀ ↽ − B ( g ) + C ( g ) A(s)↽−−⇀B(g)+C(g) Then, the container volume was doubled and equilibrium was re‑established. How many moles of A A remain?
1 answer:
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Answer:
Kinetic energy is maximum when the player hits the ball.
Explanation:
Kinetic energy , where m is the mass and v is the velocity.
So kinetic energy is proportional to square of velocity.
Velocity is maximum when the player hits the ball.
So kinetic energy is maximum when the player hits the ball.
We have that F=ma from the 2nd Newton law where F is the force, m is the mass and a is the acceleration. Suppose we have that F' is the new force and m' is the new mass. Then, we have that a'=F'/m' still, by rearranging Newton's law. We are given that F'=2F and m'=m/2. Hence,
But now, we have from F=ma, that a=F/m and we are given that a=1m/s^2.
We can substitute thus, a'=4a=4*1m/s^2=4m/s^2.
But now, we have from F=ma, that a=F/m and we are given that a=1m/s^2.
We can substitute thus, a'=4a=4*1m/s^2=4m/s^2.
Answer: 117.8 nm
Explanation:
Given,
Nonreflective coating refractive index : n = 1.21
Index of refraction: = 1.52
Wave length of light = λ = 570 nm =
Hence, the minimum thickness of the coating that will accomplish= 117.8 nm
Answer:
The answer to your question is: total energy = 30100.4 J
Explanation:
Kinetic energy (KE) is the energy due to the movement of and object, its units are joules (J)
Data
mass = 1280 kg
speed = 4.92 m/s
Force = 509 N
distance = 28.7 m
Formula
Work = Fd
Process
- Calculate Kinetic energy
- Calculate work
- Add both results
KE =
KE = 15492.1 J
Work = (509)(28.7)
Work = 14608.3 J
Total = 15492.1 + 14608.3
Total energy = 30100.4 J