A 5.20 mol 5.20 mol sample of solid A A was placed in a sealed 1.00 L container and allowed to decompose into gaseous B B and C
. C. The concentration of B B steadily increased until it reached 1.10 M, 1.10 M, where it remained constant. A ( s ) − ⇀ ↽ − B ( g ) + C ( g ) A(s)↽−−⇀B(g)+C(g) Then, the container volume was doubled and equilibrium was re‑established. How many moles of A A remain?
1 answer:
You might be interested in
The force of gravity between the astronauts is
Explanation:
The magnitude of the gravitational force between two objects is given by:
where :
is the gravitational constant
are the masses of the two objects
r is the separation between them
In this problem, we have two astronauts, whose masses are:
While the separation between the astronauts is
r = 2 m
Substituting into the equation, we can find the gravitational force between the two astronauts:
Learn more about gravitational force:
#LearnwithBrainly
Answer:
a) Initial speed of the ball = 14.45 m/s
b) At height 6 m speed of ball = 9.55 m/s
c) Maximum height reached = 10.65 m
Explanation:
a) We have equation of motion , where s is the displacement, u is the initial velocity, t is the time taken and a is the acceleration.
s = 6 m, t = 0.5 seconds, a = acceleration due to gravity value = -9.8
Substituting
Initial speed of the ball = 14.45 m/s
b) We have equation of motion , where v is the final velocity
s = 6 m, u = 14.45 m/s, a = -9.8
Substituting
So at height 6 m speed of ball = 9.55 m/s
c) We have equation of motion , where v is the final velocity
u = 14.45 m/s, v =0 , a = -9.8
Substituting
Maximum height reached = 10.65 m