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DaniilM [7]
3 years ago
8

The components of vector A are:

Physics
1 answer:
dolphi86 [110]3 years ago
6 0

Answer:

              arctg (- 6.5 / 6.0) = -47.2906° ~ 47

               Ans.    360° - 47°= 133°

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A physics teacher performed a demonstration for a science class by pulling a crate across the floor
nika2105 [10]

Answer:

An opposing force caused by friction produced a lower acceleration than calculated.

Explanation:

3 0
3 years ago
A baby was born on his due date, but doctors determined that a valve in his heart was too short to adequately pump blood to his
Ivanshal [37]

Answer:

He had a cogenital condition

Explanation:

cogenital conditions are present before or at the time of birth and are considered birth defects

3 0
3 years ago
Determine the acceleration that results when a 12 N net force is applied to a 3 kg object.
Vadim26 [7]

Heya!!

For calculate aceleration, let's applicate second law of Newton:

\boxed{F=ma}

⇒ Being:

→ F = Force = 12 N

→ m = Mass = 3 kg

→ a = aceleration = ?

Lets replace according formula and leave the "a" alone:

12\ N = 3\ kg * \textbf{a}

\textbf{a} = 12\ N / 3\ kg

\textbf{a} = 4\ m/s^{2}

Result:

The aceleration of the object is of <u>4 m/s²</u>

3 0
3 years ago
What nuclear reaction is the energy source of a white dwarf?
sammy [17]

Answer:

Multiple choice answer would be "None"

Explanation:

White dwarfs are radiating stored heat from earlier reactions.  

Technically, it would be the last fusion stage the star went through  

BEFORE it became a white dwarf, but that's nit-picking.

7 0
4 years ago
A circus performer on a pair of stilts exerts a pressure of 32 kPa on the ground. If the performer stands on one stilt, what pre
Agata [3.3K]

Answer:

64 kPa

Explanation:

The pressure exerted by a force on a surface is given by

p=\frac{F}{A}

where

p is the pressure

F is the force

A is the area on which the force is exerted

In this problem, let's call:

F = the weight of the performer, which is the force

A = the area of 1 stilt

At the beginning, the performer is standing on both stilts, so the area on which he exerts pressure is 2A. So the pressure is

p=\frac{F}{2A}=32 kPa (1)

Later, he stands on one stilt only. The force exerted is still the same (his weight), however, the area is now reduced to A; therefore, the new pressure is

p'=\frac{F}{A} = 2(\frac{F}{2A})=2p

which is twice the value calculated in (1); so, the new pressure is

p'=2(32)=64 kPa

3 0
4 years ago
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