Answer:
46 m at 9.5 degrees east of south
Explanation:
The car's speed was zero at the beginning of the 12 seconds,
and 18 m/s at the end of it. Since the acceleration was 'uniform'
during that time, the car's average speed was (1/2)(0 + 18) = 9 m/s.
12 seconds at an average speed of 9 m/s ==> (12 x 9) = 108 meters .
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That's the way I like to brain it out. If you prefer to use the formula,
the first problem you run into is: You need to remember the formula !
The formula is D = 1/2 a T²
Distance = (1/2 acceleration) x (time in seconds)²
Acceleration = (change in speed) / (time for the change)
= (18 m/s) / (12 sec)
= 1.5 m/s² .
Distance = (1/2 x 1.5 m/s²) x (12 sec)²
= (0.75 m/s²) x (144 sec²) = 108 meters .
According to Newton’s second law of motion:
F=ma
=80*0.5
=40N
<h3>
Answer:</h3>
800 meters
<h3>
Explanation;</h3>
<u>We are given;</u>
- Speed as 40 m/s
- Time as 20 seconds
We are required to determine the distance traveled
- Speed refers to the rate of change in distance.
- It is given by;
Speed = Distance ÷ time
Rearranging the formula;
Distance = speed × time
In this case;
Distance = 40 m/s × 20 sec
= 800 meters
Thus, the distance traveled by the car is 800 m
