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2 years ago

13

A number has the same digit in its hundreds place and it's hundredths place how many times greater is the value of the digit in

the hundreds place than the value of the digit in the hundredths pace

1 answer:

mash [69]2 years ago

8 0

Answer:

I just need 5 points for brainly please give me 5 stars

Step-by-step explanation:

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-1,2,5,7...with these numbers while using multiplaction, divison, addition, and subtraction, how would u get positive 24

baherus [9]

By adding two positives together, or a big positive number with a small negative number.

4 0

3 years ago

15) Find the value of x in the given square<br> Area = 34 in

lyudmila [28]

Answer:

Area of a square is given by:

A = a2

where a = length of side

6 0

3 years ago

Stephen uses \dfrac{2}{25}

zepelin [54]

Answer:

$13\dfrac{3}{4}$ servings$

Step-by-step explanation:

Stephen uses $\dfrac{2}{25}$ kilograms of tofu in each serving of his dish.

He has $1\dfrac{1}{10}$ kilograms of tofu.

We want to determine how many servings Stephen can make.

To do this, we divide the total weight of tofu by the weight per serving.

$\dfrac{\text{Total Weight(in kg)}}{\text{Weight(kg) per serving}} =\dfrac{1\dfrac{1}{10}}{ \dfrac{2}{25}}\\ = \dfrac{11}{10}\div \dfrac{2}{25}\\\\= \dfrac{11}{10}X \dfrac{25}{2}\\\\= \dfrac{11X25}{10X2}\\\\= \dfrac{275}{20}\\\\=13\dfrac{3}{4}$ servings$

Stephen can make $13\dfrac{3}{4}$ servings$ .

6 0

3 years ago

What percent of one hour is 25 minutes?

igomit [66]

Answer:

41.667% or 42%

Step-by-step explanation:

25/60

simplify

5/12 = 41.667

3 0

3 years ago

What is the equation of the asymptote? f (x) = 3^x-5+1<br> y=?

Natasha_Volkova [10]

The equation of the asymptote is $y=1$

Explanation:

The given equation is $f(x)=3^{x-5}+1$

We need to determine the horizontal asymptote of the equation.

The given equation is of the exponential function of the form $f(x)=c \cdot n^{a x+b}+k$ and has a horizontal asymptote $y=k$

Hence, from the above equation, the value of k is 1.

Therefore, we have,

$k=1$

Thus, the horizontal asymptote is $y=1$

Therefore, the asymptote of the equation is $y=1$

4 0

3 years ago