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baherus [9]
3 years ago
13

A number has the same digit in its hundreds place and it's hundredths place how many times greater is the value of the digit in

the hundreds place than the value of the digit in the hundredths pace
Mathematics
1 answer:
mash [69]3 years ago
8 0

Answer:

I just need 5 points for brainly please give me 5 stars

Step-by-step explanation:

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How many centimeters are in 8 feet, given that 1 in. 2.54 cm.​
Delicious77 [7]

Answer:

243.84

Step-by-step explanation:

We change feet to inches, and inches to cm.

1 ft = 12 in.

1 in. = 2.54 cm

8 ft * (12 in.)/(1 ft) * (2.54 cm)/(1 in.) = 243.84 cm

8 ft = 243.84 cm

3 0
3 years ago
Read 2 more answers
John lost 1.44 kilograms after a week of exercise. One kilogram is equal to approximately 2.2 pounds. How many pounds did John l
uranmaximum [27]

Answer:

Step-by-step explanation:

1.44x2.2=3.168 pounds

7 0
3 years ago
1. Evaluate 7m + 3mn; when m=8 and n=14?
FrozenT [24]

Answer:

1. 392

2. 75

3. 12x^{2} - 5x -2

Step-by-step explanation:

1. 7×8 + 3×8×14 = 56 + 336 = 392

2. 675 ÷ (6 + 3) = 675 ÷ 9 = 75

3. 12x^{2} + 3x - 8x - 2 = 12x^{2} -5x-2

3 0
4 years ago
Can an object be in pure translation as well as in pure rotation simultaneously?
Inessa [10]
  <span>"Pure translational" motion means the object is moving from place to place but isn't rotating at all. Mathematically, that means every point on the object has the same velocity vector as every other point on the object. For example, say you have a box that's sliding along the ground, and say each corner on the box is moving at 15 feet per second at an angle of 26 degrees west of north. Since every point on the box has the same velocity vector, the motion is "pure translational." 

"Pure rotational" motion means the object is rotating, but its position in space isn't changing. Mathematically, that means that every point on the object moves in a circle around some axis (usually through the object's center of mass).

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
5 0
3 years ago
Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

\sigma = 6

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

P(\bar X \:>\:75.9)

We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

5 0
3 years ago
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