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Dovator [93]
3 years ago
7

Express parametrically a point on a parabola (y-1) ssquare=x

Mathematics
1 answer:
sdas [7]3 years ago
3 0

Answer:

Conversely, given a pair of parametric equations with parameter t, the set of points (f(t), g(t)) form a curve in the plane.

As an example, the graph of any function can be parameterized. For, if y = f(x) then let t = x so that

x = t,   y = f(t).

is a pair of parametric equations with parameter t whose graph is identical to that of the function. The domain of the parametric equations is the same as the domain of f.

Example The parametric equations

x = t,   y = t2

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What's 9 + 10 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
san4es73 [151]

Answer:

19

Step-by-step explanation:

9 + 10 = 19

3 0
3 years ago
Read 2 more answers
On a piece of paper, show how to find the slope between these two points: (-1,5) and (3,13). Show all of your work and simplify
dybincka [34]
Use the formula m = y2 - y1
————
x2 - x1
(-1 is x1, 5 is y1) (3 is x2, 13 is y2)
13 - 5 8
——— = — = 2
3 - (-1) 4

2 is the slope
6 0
3 years ago
There is a red, orange, yellow, green, blue, and purple card placed in a box. (six total, one of each color). You are asked to r
GrogVix [38]

Answer:

Step-by-step explanation:

If you are doing probability with replacement they will all be 1/6 each time.

total there is 6/6. If you draw a yellow card first it's 1/6 then replace it and draw a blue it is still 1/6. so you take those two probabilities and multiply them (1/6)*(1/6)=1/36 1*1=1 and 6*6=36.

Your answer is 1/36

7 0
2 years ago
Determine which of the following relations represent a function.
Darina [25.2K]

Answer:

B

Step-by-step explanation:

In a function, each input (x) must match with one output (y). So, if there are two sets of coordinates with the same y value, that's not a function.

5 0
3 years ago
Tan x + sqrt(3) = - 2 tan x
Svet_ta [14]

9514 1404 393

Answer:

  nπ -π/6 . . . for any integer n

Step-by-step explanation:

  tan(x) +√3 = -2tan(x) . . . . . given

  3tan(x) = -√3 . . . . . . . . . . . add 2tan(x)-√3

  tan(x) = -√3/3 . . . . . . . . . . divide by 3

  x = arctan(-√3/3) = -π/6 . . . . use the inverse tangent function to find x

This is the value in the range (-π/2, π/2). The tangent function repeats with period π, so the set of values of x that will satisfy this equation is ...

  x = n·π -π/6 . . . . for any integer n

8 0
3 years ago
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