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Fed [463]
3 years ago
8

Find the value of x

Mathematics
1 answer:
marishachu [46]3 years ago
5 0

Answer:

x = 5

Step-by-step explanation:

6 - 8x = 6x - 8x - 24

(add the x's on each side)

6 - 8x = -2x - 24

(pass -2x on the other side (adding))

6 - 6x = -24

(pass the 6 to the other side (subtracting))

- 6x = - 30

(divide by -6 on  both sides)

x = 5

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Which region represents the solution to the given system of inequalities? <br> A<br> B<br> C<br> D
Semenov [28]

Answer:

a

Step-by-step explanation:

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3 years ago
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42 kg of tomatoes costs $252. how many kilograms of tomatoes can you get with $126
Softa [21]

Answer:

21 Kg of tomatoes

Step-by-step explanation:

$252 / 42 kg = $6 per kg

$126 / $6 = 21 Kg

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Andre says that 5 3/4 + 2 1/4 = 7 1/2 because 7 4/8 = 7 1/2. Identify his mistake. Draw a picture to prove that he is wrong.
MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

The given expression is

5\frac{3}{4}+2\frac{1}{4} =7\frac{4}{8}=7\frac{1}{2}

We will rewrite the expression

\frac{23}{4}+\frac{9}{4} =\frac{60}{8}=7\frac{1}{2}

When we add the fraction

\frac{23+9}{4} = \frac{32}{4} = 8

While Andre says the answer is 7\frac{1}{2}

because Andre added the denominator where he has to make a common denominator that should be 4 instead of 8.

Andre made mistake in this step

Picture is given below :

3 0
4 years ago
A sample of 900 college freshmen were randomly selected for a national survey. Among the survey participants, 372 students were
Rufina [12.5K]

Answer:

a) ME=2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.0423

b) 0.413 - 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.371

Step-by-step explanation:

1) Data given and notation  

n=900 represent the random sample taken    

X=372 represent the students were pursuing liberal arts degrees

\hat p=\frac{372}{900}=0.413 estimated proportion of students were pursuing liberal arts degrees

\alpha=0.01 represent the significance level

z would represent the statistic (variable of interest)    

p_v represent the p value (variable of interest)    

p= population proportion of students were pursuing liberal arts degrees

2) Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

The margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

If we replace we have:

ME=2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.0423

And replacing into the confidence interval formula we got:

0.413 - 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.371

0.413 + 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.455

And the 99% confidence interval would be given (0.371;0.455).

We are confident (99%) that about 37.1% to 45.5% of students were pursuing liberal arts degrees.

7 0
3 years ago
Help me I wasn't here
Anna007 [38]

Answer:

6/8 or 3/4 or 75%

Step-by-step explanation:

6 0
3 years ago
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