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ioda
2 years ago
15

On four exams, Wallace’s grades were 79,93,91, and 68. What grade must he obtain on his fifth exam to have an 80 average?

Mathematics
2 answers:
neonofarm [45]2 years ago
7 0
(79 + 93 + 91 + 68 + x) / 5 = 80
(331 + x) / 5 = 80.....multiply both sides by 5
331 + x = 80 * 5
331 + x = 400
x = 400 - 331
x = 69 <=== he would have to make at least a 69
Leona [35]2 years ago
7 0

(79 + 93 + 91 + 68 + x) / 5 = 80

Simplify

(331 + x)/5 = 80

Multiply 5 to both sides to isolate the x.

331 + x = 400

Isolate the x. Subtract 331 from both sides

x + 331 (-331) = 400 (-331)

x = 69

69 is your answer

hope this helps

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Connor rolled a die 6 times. A 2 occurred three times. Why isn't the theoretical probability 3/6 instead of 1/6?​
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6 0
2 years ago
Area of a triangle is given by the formula A=1/2 bh. The area of the triangle shown to the right is 56 sq. units. Find its base
Westkost [7]
Given

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height=x+4

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area=56 square units

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times bot sides by 2
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expand
112=2x²+14x+24
divide both sides by 2
56=x²+7x+12
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factor
waht 2 numbers mulitply to get -44 and add to get 7
11 and -4
0=(x-4)(x+11)
set to 0

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x=4


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x=4 and base=14 and height=8

8 0
3 years ago
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