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3 years ago

8

What is the benefit of using a coordinate graph?

1 answer:

slavikrds [6]3 years ago

8 0

Answer:

Step-by-step explanation:

The graph of a function on coordinate axes (x- and y- axes) provides a good, fast, visual feel for the behavior of the function as the independent variable (x) increases.

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What is the product ?

Olenka [21]

Answer:

The answer to your question is:

Step-by-step explanation:

$\frac{x^{2}-16 }{2x + 4} \frac{x^{3}-2x^{2} + x }{x^{2}+ 3x - 4}$

Factorize $\frac{(x+4)(x-4)}{2(x+2)} \frac{x(x^{2}-2x + 1) }{(x+4)(x-1)}$

Factorize $\frac{(x+4)(x-4)}{2(x+2)} \frac{x(x-1)^{2} }{(x+4)(x-1)}$

Simplify $\frac{x(x-4)}{2(x+2)}$

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3 years ago

In a transformation, the final figure is called.

Viktor [21]

Answer:

A transformation is a general term for four specific ways to manipulate the shape and/or position of a point, a line, or geometric figure. The original shape of the object is called the Pre-Image and the final shape and position of the object is the Image under the transformation.

6 0

3 years ago

A large aquarium should contain 10,000 liters of water when it is filled correctly. Fish will get sick if the aquarium gets down

pashok25 [27]

Answer:

9016 litres left

Step-by-step explanation:

The fish were not sick.

You would multiply 20.5 by 48 which is the amount of hours in 2 days then subtract that amount from 10000 to see how much is left

8 0

3 years ago

Please help me answer this question its urgent

yarga [219]

Answer:

Step-by-step explanation:

1). $\frac{2}{3}n-\frac{3}{4}n+\frac{1}{6}n+2\frac{2}{9}n$

= $\frac{2}{3}n-\frac{3}{4}n+\frac{1}{6}n+(2+\frac{2}{9})n$

= $(\frac{2}{3}-\frac{3}{4}+\frac{1}{6})n+(2+\frac{2}{9})n$

= $(\frac{8}{12}-\frac{9}{12}+\frac{2}{12})n+(2+\frac{2}{9})n$

= $\frac{(8-9+2)}{12}n+(2+\frac{2}{9})n$

= $\frac{1}{12}n+(2+\frac{2}{9})n$

= $(\frac{1}{12}+2+\frac{2}{9})n$

= $(\frac{3}{36}+\frac{72}{36}+\frac{8}{36})n$

= $\frac{83}{36}n$

= $2\frac{11}{36}n$

2). $\frac{2}{5}g-\frac{1}{6}-g+\frac{3}{10}g-\frac{4}{5}$

= $(\frac{2}{5}-1+\frac{3}{10})g-(\frac{1}{6}+\frac{4}{5})$

= $(\frac{4}{10}-\frac{10}{10}+\frac{3}{10})g-(\frac{5}{30}+ \frac{24}{30})$

= $(\frac{4-10+3}{10})g-(\frac{5+24}{30})$

= $\frac{-3}{10}g-\frac{29}{30}$

= $-\frac{3}{10}g-\frac{29}{30}$

3). $i+6i-\frac{3}{7}i+\frac{1}{3}h+\frac{1}{2}i-h+\frac{1}{4}h$

= $7i-\frac{3}{7}i+\frac{1}{2}i+\frac{1}{3}h-h+\frac{1}{4}h$

= $(7-\frac{3}{7}+\frac{1}{2})i+(\frac{1}{3}-1+\frac{1}{4})h$

= $(\frac{98}{14} -\frac{6}{14}+\frac{7}{14})i+(\frac{4}{12}-\frac{12}{12}+\frac{3}{12})h$

= $(\frac{98-6+7}{14})i+(\frac{4-12+3}{12})h$

= $\frac{99}{14}i-\frac{5}{12}h$

6 0

3 years ago

Can Someone help me?

aleksandrvk [35]

I think the answer is A. 3.

B. no, to big a number

C. no, to small a number

D. no, again, too big a number.

Have a nice day and hope this helps!

6 0

3 years ago