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blondinia [14]
3 years ago
13

10(14-6) what is value of expression

Mathematics
2 answers:
Annette [7]3 years ago
4 0

Answer:

80

Step-by-step explanation:

vredina [299]3 years ago
4 0

Answer:

the value of expression is 80

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The answer would be C.2
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(cos x - (sqrt 2)/2)(sec x -1)=0
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(\cos x-\frac{\sqrt{2}}{2})(\sec x-1)=0 [/tex]

=(\cos x-\frac{1}{\sqrt{2}})(\sec x-1)=0 [/tex]

\frac{(\sqrt{2}\cos x-1)}{\sqrt{2}}(\frac{1}{\cos x\ }-1)=0

(Reciprocal Identity)

(\frac{^{\sqrt{2}\\cos  x-1}}{^{\sqrt{2}}})(\frac{1-\cos x}{\cos x})=0

\frac{^{(\sqrt{2}\cos x-1})}{\sqrt{2}}\frac{(1-\cos x)}{\cos x}=0

(\sqrt{2}\cos x-1}){(1-\cos x)}=0 (ZeroProduct Property)

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and

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6 0
3 years ago
Read 2 more answers
9 batteries cost 18 dollars what's the rate and unit rate
Vanyuwa [196]
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8 0
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Round 5 358 708 to the nearest million​
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4 0
1 year ago
Consider the function f(x) = x2 + 2x – 35. If one of the zeros of the
Whitepunk [10]

If one zeros is x= -7 then the other zero is x=5

Step-by-step explanation:

We are given the function: f(x) = x^2 + 2x-35

If one zeros of the function is x=-7 we need to find other zero of the function.

We can find zeros of the quadratic equation by factorizing the equation

f(x) = x^2 + 2x-35

Factorizing the quadratic equation:

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So, if one zeros is x= -7 then the other zero is x=5

Keywords: Solving Quadratic Equation

Learn more about Solving Quadratic Equation at:

  • brainly.com/question/10771256
  • brainly.com/question/2568692
  • brainly.com/question/1332667

#learnwithBrainly

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