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3 years ago

When 6 is subtracted from the square of a number, the result is 5 times the number. Find the POSITIVE solution.

Mathematics

1 answer:

valkas [14]3 years ago

6 0

:) Brainliest pls??

Answer:

The positive solution is 6.

Step-by-step explanation:

x^2 - 6 = 5x (Subtract 5x from both sides)

x^2 -5x - 6 = 0 (We can factor this, so there is no need to use the quadratic formula)

(x - 6)(x + 1) = 0

If the product of the two terms is zero then either one being equal to zero will cause the whole expression to be zero.

The solutions are:

x - 6 = 0 (Add 6 to both sides)

x = 6

x + 1 = 0 (Subtract 1 from both sides)

x = -1

The positive solution is 6.

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What is the simplified form of 12x/900x²y4z6?

zalisa [80]

Answer:

$360xy^2|xz^3|$

Step-by-step explanation:

Given expression:

$12x \sqrt{900x^2y^4z^6}$

$\textsf{Apply radical rule} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}:$

$\implies 12x \sqrt{900}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}$

Replace 900 with 30² :

$\implies 12x \sqrt{30^2}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}$

$\textsf{Apply radical rule} \quad \sqrt{a^2}=a, \quad a \geq 0:$

$\implies 12x \cdot 30|x|\sqrt{y^4}\sqrt{z^6}$

$\implies 360x|x|\sqrt{y^4}\sqrt{z^6}$

(We need to use the absolute value of √x² since the x term was originally to the power of 2, which means the value of x² is always positive since the exponent is even).

$\textsf{Apply exponent rule} \quad \sqrt{a^m}=a^{\frac{m}{2}}:$

$\implies 360x|x|\cdot y^{\frac{4}{2}}\cdot z^{\frac{6}{2}}$

Simplify:

$\implies 360xy^2|xz^3|$

(We need to use the absolute value of z³ since the z term was original to the power of 6, which means the value of z⁶ is always positive since the exponent is even).

7 0

2 years ago

What is the volume of a cube with a side length that measures 8cm? ANWSER ASAP please

NeTakaya

What you do is 8 x 8 x 8 and cube your number
=512

3 0

3 years ago

Read 2 more answers

What is the next sequence 3.1 3.1 1 33.11 33.111

MrMuchimi

The next number in the sequence should be 333.111

7 0