Answer:
The value of x component changes at a rate of
units per second
Step-by-step explanation:
We are given that 
Differentiating on both sides with respect to time we get

It is given that
Solving for
we get

Given :-
- y varies directly as x, and y=14 when x=4.
To Find :-
- the value of y when x=9 .
Solution :-
<u>A</u><u>c</u><u>c</u><u>o</u><u>r</u><u>d</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>o</u><u> </u><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>,</u>
<u>When</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>1</u><u>4</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>4</u><u> </u><u>,</u>
<u>W</u><u>h</u><u>e</u><u>n</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>9</u><u> </u><u>,</u>
- y = 7/2*9
- y = 63/2
- y = 31.5
Answer:
Track 2
Step-by-step explanation:
180 degrees would turn the train completely around so if it entered on track 2 then it left on track 2
6x+3y=33..........(1)
4x+y=15
y=15-4x.........(2)
substitute value of y from (2) in (1)
6x+3(15-4x)=33
distribute 3 over the bracket
6x+45-12x =33
-6x=33-45
-6x=-12
x=2
plugging this value of x in equation 2 we get
15-4x=y
15-4(2)=y
y=15-8
y=7
Answer is x=2 and y=7