Since 111 is greater than 33, I will assume that you meant 11 votes for a candidate. Also, assuming that each student can vote only once, the answer would be
11/33 x 100=33.333333...
About 33.333 of the voters voted for candidate a.
43 can fit into 93 two whole times.
After that, there's only room for another 7 inside the 93,
so there's no way to stuff the whole 43 in there again.
Answer:
The answer would be Part F
A.

The denominator of the second number goes down one because you aren't replacing the initial marble pulled, making the amount of marbles in the bag go down, but not affecting the white count because you pulled a purple marble.
b.

The same can be said about the denominator for this problem, but not the numerator. The numerator must go down one number as well, because you already chose one white marble, taking one of the white marbles out of the bag, leaving you with one solitary, white marble.
c.
Chance of selecting two purple marbles:
<u />

Chance of selecting two white marbles:

<u>Chance of selecting two purple</u> vs. <em>Chance of Selecting 2 white:</em>
<u>0.583</u>><em>0.278</em>.
It is more likely to select 2 purple marbles.
Hope this helps!